Question
In: Civil Engineering
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23 with an elevation of 903.00 ft. Using a vertical curve of length 493 ft., find the elevation of each full station along the curve. What is the station of the turning point on the curve? {If your calculations result in more than 6 stakes on the curve, evaluate only the first 6}.
Solutions
Ally Wells answered 11 months agoRelated Solutions
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A 500 feet equal tangent vertical curve connects two tangents that intersects at station 5+34.00 and...
A 500 feet equal tangent vertical curve connects two tangents
that intersects at station 5+34.00 and elevation 1210 ft. The
initial grade is +4% and the final grade is -2.5%.
i. determine the station and elevation of the high point, PVC and
PVT
ii. What will you recommend as the maximum safe design speed for
this road to provide adequate stopping sight distance?
A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of...
A vertical curve has its PVI at station 14+75.00 and elevation
76.29 ft. The grade of the back tangent is 3.4%, the grade of the
forward tangent is -4.8%, and the curve length is 450 ft.
Determine the stations and elevations of the BVC and EVC.
Determine the location and elevation of the high point of the
curve.
Determine the curve elevation at station 14+00 and station
16+00.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station
elevations for an unequal-tangent vertical curve to fit the
requirements in Problems 2 through 5.
2. A +3.50% grade meets a −2.25% grade
at station 60+00 and elevation 1310.00 ft. Length of first curve
600 ft, second curve 400 ft.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station elevations for an
unequal-tangent vertical curve to fit the requirements in Problems
2 through 5.
4. Grades g1 of +5.00% and g2 of -2.00%, meet at the VPI at
station 4+300 and elevation 154.960 m. Lengths of curves are 200
and 350 m. (Use 40-m stationing)
Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data...
Tabulate station elevations (stakeout at full stations) for an
equal-tangent vertical curve for the following data given. (20 pts)
• 500-ft curve • g1 = -3.00% • g2 = -1.25% • VPI at station 38 + 00
and elevation 560.00 ft
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements of grade...
Compute and tabulate full-station elevations
for an unequal-tangent vertical curve to fit the requirements of
grade g1 = +1.25%, g2 = +3.75%, VPI at station 62+00 and elevation
1053.95 ft, L1 = 500 ft and L2 = 600 ft.
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and...
A 276 m equal-tangent sag vertical curve has the PVC at station
3 + 700.000 and elevation 321 m. The initial grade is -3.5% and the
final grade is +0.5%. Determine the stationing and elevation of the
PVI, the PVT, and the lowest point on the curve.
A vertical summit curve has tangent grades of +2.5% and -1.5% intersecting at station 12+460.12 at...
A vertical summit curve has tangent grades of +2.5% and -1.5%
intersecting at station 12+460.12 at an elevation of 150m above sea
level. If the length of the curve is 182m: a. Compute the length of
the passing sight distance.
b. Compute the stationing of the highest point of the curve.
c. Compute the elevation of the highest point of the curve.
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