Question
In: Civil Engineering
A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of...
A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of the back tangent is 3.4%, the grade of the forward tangent is -4.8%, and the curve length is 450 ft.
- Determine the stations and elevations of the BVC and EVC.
- Determine the location and elevation of the high point of the curve.
- Determine the curve elevation at station 14+00 and station 16+00.
Solutions
Ally Wells answered 2 months agoRelated Solutions
A −2.60% grade meets a +1.95% grade at station 44+25 and elevation 3386.96 ft, 315-ft curve,...
A −2.60% grade meets a +1.95% grade at station 44+25 and
elevation 3386.96 ft, 315-ft curve, stakeout at half stations.
Part A
Tabulate station elevations for an equal-tangent parabolic curve
for the data given above.
Express your answers, separated by commas, to six significant
figures from lowest to highest elevation.
ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft
SubmitRequest Answer
Provide Feedback
Curve 2: A +7.00% grade meets a -6.00% grade at station 4+80 and elevation 705.70 ft,...
Curve 2: A +7.00% grade meets a -6.00% grade at station 4+80 and
elevation 705.70 ft, 80-ft curve, staked 10ft apart. Get a rough
estimate in cubic yards of how much soil that must be brought in
(fill) and/or removed (cut) to create a 14-foot wide roadway that
starts at your PVC/BVC, ends at your PVT/EVC, and follows your
curve elevations. Make sure to state which curve your group was
assigned in the calculations. Trapezoidal Area Estimation is key.
ground...
Given the following vertical curve data: PVI at 19+ 00,L= 500 ft,g1= +2.5%,g2= -1%, and elevation...
Given the following vertical curve data: PVI at 19+ 00,L= 500
ft,g1= +2.5%,g2= -1%, and elevation of PVI = 723.86 ft.Compute the
elevationsof the curve summit (i.e. high
point)andfullstations.Assume that all symbols have their usual
meaning.
A 0% grade meets a 3% grade at station 24+00.00 and an elevation of 372.15 ft....
A 0% grade meets a 3% grade at station 24+00.00 and an elevation
of 372.15 ft. For a passing sight distance of 2,000 ft, find the
following:
a. Minimum length of the vertical curve that allows for passing
using the minimum curve length equations.
b. Calculate the elevation of the middle point of the curve.
c. Calculate the elevation of the road at station 23+00.00.
A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents...
A 1000-ft vertical curve connects a -1% grade to a -3.5% grade.
If the vertical tangents intersect at sta. 38+60.24 and elevation
1,400.13 ft, develop an Excel spreadsheet to calculate the
elevations of the grade line at each station from sta. 31+00 to
45+00. Include the elevations of the PVC and PVT.
A −2.60% grade meets a +1.70% grade at station 44+25 and elevation 3386.96 ftft, 305-ftft curve,...
A −2.60% grade meets a +1.70% grade at station 44+25 and
elevation 3386.96 ftft, 305-ftft curve, stakeout at half
stations.
Tabulate station elevations for an equal-tangent parabolic curve
for the data given above.
Express your answers, separated by commas, to six significant
figures from lowest to highest elevation.
The following information is given about a vertical curve: Station of VPI = 150+00.00 feet Elevation...
The following information is given about a vertical curve:
Station of VPI = 150+00.00 feet
Elevation of VPI = 2500.00 feet
L = 1000.00 feet
g1 = -3.0%
g2 = 1.0%
(a) Find the stations and elevations of the BVC and EVC.
(b) Also, what is the station and elevation of the lowest point
of the curve?
(c) Calculate the first and second differences on the curve
elevations of the full stations
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- The following time series shows the sales of a particular product over the past 12 months....
- Would the voltage of a battery in circuit be larger or smaller than the voltage of...
- The current asset section of the Excalibur Tire Company’s balance sheet consists of cash, marketable securities,...
- Part 1: Explain and provide a real life business example for equivalent units. Explain the importance...
- A company produces three different type of chocolates. A, B, and C. The sales volume for...
- When considering labeling someone with a disorder it is important that we use the most up...
- 7. The director of career advising at Rutgers want to use decision analysis to provide...
ADVERTISEMENT