Question
In: Civil Engineering
A 500 feet equal tangent vertical curve connects two tangents that intersects at station 5+34.00 and...
A 500 feet equal tangent vertical curve connects two tangents
that intersects at station 5+34.00 and elevation 1210 ft. The
initial grade is +4% and the final grade is -2.5%.
i. determine the station and elevation of the high point, PVC and
PVT
ii. What will you recommend as the maximum safe design speed for this road to provide adequate stopping sight distance?
Solutions
Ally Wells answered 5 months agoRelated Solutions
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a
PVI station of 310+11.23 with an elevation of 903.00 ft. Using a
vertical curve of length 493 ft., find the elevation of each full
station along the curve. What is the station of the turning point
on the curve? {If your calculations result in more than 6 stakes on
the curve, evaluate only the first 6}.
An equal-tangent crest vertical curve connects an initial grade of +2.5% and a final grade of...
An equal-tangent crest vertical curve connects an initial grade
of +2.5% and a final grade of –0.5%. The curve is designed for 70
mi/h and the station of the PVT is 132+62 and is at elevation 833
ft. What is the station and elevation of the curve's high
point?
A vertical sag curve connects two tangents with grades -3% and +2% with the design speed...
A vertical sag curve connects two tangents with grades -3% and
+2% with the design speed of
100 km/h.
(a) Calculate the available sight distance and the length of the
vertical curve using the minimum
flatness of curve that will satisfy the headlight criterion during
dark conditions. Assume the
height of the headlight above the pavement is 0.6 m and the angle
of the light beam upward
from the axis of beam is 1.
(a) Assuming that the length of...
A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents...
A 1000-ft vertical curve connects a -1% grade to a -3.5% grade.
If the vertical tangents intersect at sta. 38+60.24 and elevation
1,400.13 ft, develop an Excel spreadsheet to calculate the
elevations of the grade line at each station from sta. 31+00 to
45+00. Include the elevations of the PVC and PVT.
Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data...
Tabulate station elevations (stakeout at full stations) for an
equal-tangent vertical curve for the following data given. (20 pts)
• 500-ft curve • g1 = -3.00% • g2 = -1.25% • VPI at station 38 + 00
and elevation 560.00 ft
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and...
A 276 m equal-tangent sag vertical curve has the PVC at station
3 + 700.000 and elevation 321 m. The initial grade is -3.5% and the
final grade is +0.5%. Determine the stationing and elevation of the
PVI, the PVT, and the lowest point on the curve.
Use the following data to calculate the layout of an equal tangent vertical curve by offsets...
Use the following data to calculate the layout of an
equal tangent vertical curve
by offsets for every full station.
g1 = -1.20%
g2 = +3.50%
X PVI = 49+70
Y PVI = 5,893.48’
L = 1500’
, find the station and
elevation of the high (or low) point of the curve.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station
elevations for an unequal-tangent vertical curve to fit the
requirements in Problems 2 through 5.
2. A +3.50% grade meets a −2.25% grade
at station 60+00 and elevation 1310.00 ft. Length of first curve
600 ft, second curve 400 ft.
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