Question

In: Civil Engineering

Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements of grade...

Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements of grade g1 = +1.25%, g2 = +3.75%, VPI at station 62+00 and elevation 1053.95 ft, L1 = 500 ft and L2 = 600 ft.

Solutions

Expert Solution


Related Solutions

Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems 2 through 5. 2. A +3.50% grade meets a −2.25% grade at station 60+00 and elevation 1310.00 ft. Length of first curve 600 ft, second curve 400 ft.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems 2 through 5. 4. Grades g1 of +5.00% and g2 of -2.00%, meet at the VPI at station 4+300 and elevation 154.960 m. Lengths of curves are 200 and 350 m. (Use 40-m stationing)
Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data...
Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data given. (20 pts) • 500-ft curve • g1 = -3.00% • g2 = -1.25% • VPI at station 38 + 00 and elevation 560.00 ft
An equal-tangent crest vertical curve connects an initial grade of +2.5% and a final grade of...
An equal-tangent crest vertical curve connects an initial grade of +2.5% and a final grade of –0.5%. The curve is designed for 70 mi/h and the station of the PVT is 132+62 and is at elevation 833 ft. What is the station and elevation of the curve's high point?
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and...
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and elevation 321 m. The initial grade is -3.5% and the final grade is +0.5%. Determine the stationing and elevation of the PVI, the PVT, and the lowest point on the curve.
A vertical summit curve has tangent grades of +2.5% and -1.5% intersecting at station 12+460.12 at...
A vertical summit curve has tangent grades of +2.5% and -1.5% intersecting at station 12+460.12 at an elevation of 150m above sea level. If the length of the curve is 182m: a. Compute the length of the passing sight distance. b. Compute the stationing of the highest point of the curve. c. Compute the elevation of the highest point of the curve.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23 with an elevation of 903.00 ft. Using a vertical curve of length 493 ft., find the elevation of each full station along the curve. What is the station of the turning point on the curve? {If your calculations result in more than 6 stakes on the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23 with an elevation of 903.00 ft. Using a vertical curve of length 493 ft., find the elevation of each full station along the curve. What is the station of the turning point on the curve? {If your calculations result in more than 6 stakes on the curve, evaluate only the first 6}.
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23...
A vertical tangent at 4.7% intersects a tangent at -3.9% at a PVI station of 310+11.23 with an elevation of 903.00 ft. Using a vertical curve of length 493 ft., find the elevation of each full station along the curve. What is the station of the turning point on the curve? {If your calculations result in more than 6 stakes on the curve, evaluate only the first 6}.
An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and...
An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT