Question
In: Civil Engineering
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and...
A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and elevation 321 m. The initial grade is -3.5% and the final grade is +0.5%. Determine the stationing and elevation of the PVI, the PVT, and the lowest point on the curve.
Solutions
Ally Wells answered 9 months agoRelated Solutions
A 280m long equal tangent sag vertical curve has its PVC at chainage 2950.00m and elevation...
A 280m long equal tangent sag vertical curve has its
PVC at chainage 2950.00m and elevation 76. 520m.The initial grade
is -3.89% and the final grade is 1.02%. (20)
a. Make a neat free hand drawing to illustrate a long section of
this curve.
b. Calculate the chainage and elevation of PVI
c. Calculate the chainage and elevation of PVT
d. Calculate the chainage and elevation of the lowest point on the
curve.
Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data...
Tabulate station elevations (stakeout at full stations) for an
equal-tangent vertical curve for the following data given. (20 pts)
• 500-ft curve • g1 = -3.00% • g2 = -1.25% • VPI at station 38 + 00
and elevation 560.00 ft
A 500 feet equal tangent vertical curve connects two tangents that intersects at station 5+34.00 and...
A 500 feet equal tangent vertical curve connects two tangents
that intersects at station 5+34.00 and elevation 1210 ft. The
initial grade is +4% and the final grade is -2.5%.
i. determine the station and elevation of the high point, PVC and
PVT
ii. What will you recommend as the maximum safe design speed for
this road to provide adequate stopping sight distance?
You have a symmetrical sag vertical curve of Length = 6 stations. The entering tangent from...
You have a symmetrical
sag vertical curve of Length = 6 stations. The entering tangent
from the left has a gradient of –6% and the exiting tangent has a
gradient of +4%. The VPC Station has an elevation of 250.00 feet
(which will be your C-Value) and its station distance is measured
to be at 40+00 stations. You will now do the following:
Find the elevation
and station of the VPI.
Find the elevation
and station of the VPT
Find...
A vertical summit curve has tangent grades of +2.5% and -1.5% intersecting at station 12+460.12 at...
A vertical summit curve has tangent grades of +2.5% and -1.5%
intersecting at station 12+460.12 at an elevation of 150m above sea
level. If the length of the curve is 182m: a. Compute the length of
the passing sight distance.
b. Compute the stationing of the highest point of the curve.
c. Compute the elevation of the highest point of the curve.
Use the following data to calculate the layout of an equal tangent vertical curve by offsets...
Use the following data to calculate the layout of an
equal tangent vertical curve
by offsets for every full station.
g1 = -1.20%
g2 = +3.50%
X PVI = 49+70
Y PVI = 5,893.48’
L = 1500’
, find the station and
elevation of the high (or low) point of the curve.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station
elevations for an unequal-tangent vertical curve to fit the
requirements in Problems 2 through 5.
2. A +3.50% grade meets a −2.25% grade
at station 60+00 and elevation 1310.00 ft. Length of first curve
600 ft, second curve 400 ft.
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements in Problems...
Compute and tabulate full-station elevations for an
unequal-tangent vertical curve to fit the requirements in Problems
2 through 5.
4. Grades g1 of +5.00% and g2 of -2.00%, meet at the VPI at
station 4+300 and elevation 154.960 m. Lengths of curves are 200
and 350 m. (Use 40-m stationing)
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements of grade...
Compute and tabulate full-station elevations
for an unequal-tangent vertical curve to fit the requirements of
grade g1 = +1.25%, g2 = +3.75%, VPI at station 62+00 and elevation
1053.95 ft, L1 = 500 ft and L2 = 600 ft.
A vertical sag curve connects two tangents with grades -3% and +2% with the design speed...
A vertical sag curve connects two tangents with grades -3% and
+2% with the design speed of
100 km/h.
(a) Calculate the available sight distance and the length of the
vertical curve using the minimum
flatness of curve that will satisfy the headlight criterion during
dark conditions. Assume the
height of the headlight above the pavement is 0.6 m and the angle
of the light beam upward
from the axis of beam is 1.
(a) Assuming that the length of...
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