In: Math
2. Evaluate the following limits.
(a) lim x→1+
ln(x) /ln(x − 1)
(b) limx→2π
x sin(x) + x ^2 − 4π^2/x − 2π
(c) limx→0
sin^2 (3x)/x^2
(a)
The right limit of ln(x) at 1 is 0.
The right limit of ln(x-1) at 1 is .
Hence,
(b)
By substituting x = 2 in the function, we get the indeterminate form 0/0. Hence, we need to apply the L'Hopital's
rule.
(c)