L'Hospitals rule find the limits a) lim (tanx−secx) x→π/2- (b) lim (lnx-1) / (x-e) x→e...

L'Hospitals rule find the limits

a) lim (tanx−secx)

x→π/2-

(b) lim (lnx-1) / (x-e)

x→e

(c) lim x^(1/lnx)

x→0+

Expert Solution

milcah answered 2 years ago

Use LHopital rule to solve. lim (x-1)^(lnx) x goes to 1+

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