Question

USING MATLAB....

a.) Create anonymous functions:

fa(x)=sin(x^2)

fb(x)=sin^2(x)

b.) Evaluate them both at x=1/2 pi

c.)Evaluate them both at x=(0,1,2,...,10)^T

d.) Calculate fa(fb(2)) and fb(fa(2))

Answer 1

clc;
clear all;
%%% Answer a
fa=@(x)sin(x.^2);
fb=@(x)(sin(x)).^2;

%%% Answer b
x1=pi/2;
disp('fa at x1')
fa(x1)
disp('fb at x1')
fb(x1)
%%% Answer c
x=0:10;
disp('fa at x=0 to 10')
fa(x)'
disp('fb at x=0 to 10')
fb(x)'
%%% Answer d
disp('fb(fa(2))')
fb(fa(2))
disp('fa(fb(2))')
fa(fb(2))

fa at x1

ans =

   0.624265952639699

fb at x1

ans =

     1

fa at x=0 to 10

ans =

                   0
   0.841470984807897
-0.756802495307928
   0.412118485241757
-0.287903316665065
-0.132351750097773
-0.991778853443116
-0.953752652759472
   0.920026038196791
-0.629887994274454
-0.506365641109759

fb at x=0 to 10

ans =

                   0
   0.708073418273571
   0.826821810431806
   0.019914856674817
   0.572750016904307
   0.919535764538226
   0.078073020633754
   0.431631390896083
   0.978829740161692
   0.169841645877960
   0.295958969093304

fb(fa(2))

ans =

   0.471419918046348

fa(fb(2))

ans =

   0.631614802553066

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