Question

In: Math

You started taking the bus to work. The local transit authority says that a bus should...

You started taking the bus to work. The local transit authority says that a bus should arrive at your bus stop every five minutes. After a while, you notice you spend a lot more than five minutes waiting for the bus, so you start to keep a record.

You spend the next two months recording how long it takes for the bus to arrive to the bus stop. This give a total of sixty observations that denote the number of minutes it took for the bus to arrive (rounded to the nearest minute). These observations are hosted at

   https://mattbutner.github.io/data/bus_stop_time.csv

Load these data into R as a data frame titled bus_stop_time

Create a histogram of the time_until_bus varaible. Would you say that five minutes is a reasonable guess for the average arrival time based on this picture alone?

Create 95% confidence interval for the bus arrival times using the Z distribution. Does 5 minutes fall within the 95% confidence interval?

How would you communicate your finding to the local transit authority?

Solutions

Expert Solution

Please see the complete R code below alsong with the results

The confidenc einterval is given as

mean +- z*sd/sqrt(n), where z = 1.96 from the z table , n is number of samples

bus_stop_time <- read.csv("https://mattbutner.github.io/data/bus_stop_time.csv",header=TRUE)

# histogram

hist(bus_stop_time$time_until_bus,col="skyblue")
abline(v = mean(bus_stop_time$time_until_bus),
col = "red",
lwd = 2)

## 95% confidence interval


## upper limit
mean(bus_stop_time$time_until_bus) + 1.96*sd(bus_stop_time$time_until_bus)/sqrt(nrow(bus_stop_time))


## lowerlimit
mean(bus_stop_time$time_until_bus) - 1.96*sd(bus_stop_time$time_until_bus)/sqrt(nrow(bus_stop_time))

The results are

> ## upper limit
> mean(bus_stop_time$time_until_bus) + 1.96*sd(bus_stop_time$time_until_bus)/sqrt(nrow(bus_stop_time))
[1] 6.31626
>
>
> ## lowerlimit
> mean(bus_stop_time$time_until_bus) - 1.96*sd(bus_stop_time$time_until_bus)/sqrt(nrow(bus_stop_time))
[1] 5.28374

Based on the histogram , it is reasonable to assume 5 minutes as the average arrival time as the mean line is close to 5

we are 95% confident that the true value of the average arrival time would lie in the interval 5.28 and 6.31

Hope this helps . Please rate


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