##### Question

In: Computer Science

# #Write a function called get_integer that takes as input one #variable, my_var. If my_var can be...

#Write a function called get_integer that takes as input one
#variable, my_var. If my_var can be converted to an integer,
#do so and return that integer. If my_var cannot be converted
#to an integer, return a message that says, "Cannot convert!"
#
#For example, for "5" as the value of my_var, get_integer would
#return the integer 5. If the value of my_var is the string
#"Boggle.", then get_integer would return a string with the
#value "Cannot convert!"
#
#Do not use any conditionals or the type() function.

#Below are some lines of code that will test your function.
#You can change the value of the variable(s) to test your
#function with different inputs.
#
#If your function works correctly, this will originally
#print: 5, Cannot convert!, and 5.

print(get_integer("5"))
print(get_integer("Boggle."))
print(get_integer(5.1))

## Solutions

##### Expert Solution

# Write a function called get_integer that takes as input one
# variable, my_var. If my_var can be converted to an integer,
# do so and return that integer. If my_var cannot be converted
# to an integer, return a message that says, "Cannot convert!"
#
# For example, for "5" as the value of my_var, get_integer would
# return the integer 5. If the value of my_var is the string
# "Boggle.", then get_integer would return a string with the
# value "Cannot convert!"
#
# Do not use any conditionals or the type() function.

def get_integer(s):
try:
return int(s)
except:
return 'Cannot convert!'

# Below are some lines of code that will test your function.
# You can change the value of the variable(s) to test your
# function with different inputs.
#
# If your function works correctly, this will originally
# print: 5, Cannot convert!, and 5.

print(get_integer("5"))
print(get_integer("Boggle."))
print(get_integer(5.1)) ## Related Solutions

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