Question

C++ write a function called divideBy that takes two integers as its input and returns the remainder. If the divisor is 0, the function should return -1, else it should return the remainder to the calling function.

Answer 1

I will provide you 2 programs. 1st program in which the function has two parameters or arguments whereas in the 2nd program function without arguments. But both the program will provide you the same result

1st Program

#include<iostream> // defining header file

using namespace std;

int divideBy(int x,int y); //declaring the function with two arguments. Since the function returns integer it is declared in int type

int main() //main function

{

int a,b,c; //declaring variables

cout<<"Enter the dividend";

cin>>a;

cout<<"Enter the divisor";

cin>>b;

c=divideBy(a,b); //calling the functions by passing the values

cout<<c;

return 0;

}

int divideBy(int x,int y)   

{ //body of the function starts here

int z;

if(y==0) //checking whether the divisor is 0

z=-1;

else

z=x%y; // % is modulus operator which is used to return the remainder value

return z; //returning value to the calling function

}

2nd Program

#include<iostream>

using namespace std;

int divideBy(); //declaring function without arguments

int main()

{

int a;

a=divideBy();

cout<<a;

return 0;

}

int divideBy()

{

int x,y,z;

cout<<"Enter the dividend" //getting the inputs inside the function

cin>>x;

cout<<"Enter the divisor";

cin>>y;

if(y==0)

z=-1;

else

z=x%y;

return z;

}