In: Chemistry
Choose one answer
A 400 mOsm/1 glucose solution is:
A) Hyposmotic to a 200 mM solution of KCl
B) isosmotic to a 600 mM solution of KCl
C) Isosmotic to a 0.18% solution of KCl
D) Hyperosmotic to a 200 mM solution of KCl
E) isomotic to a 200 mM solution of KCl.
Osmoles are the number of particle moles in solution. If the solute dissociate into n particles ( n ions) in solution then its osmoles = n x no. of moles. or Osm/L = n x moles/L
Given the glucose concentration in milli Osmoles / L as 400 mOsm/L
That is there are 400 milliOsmoles of glucose present in 1 L of the solution.
since glucose doesn't dissociate in solution its molar concentration and osmolar concentration are the same.
We know that KCl dissociates in to K+ and Cl- ions [ 2 particles]
therefore 200 mM of KCl = 2 x 200 = 400 mOsm/L of KCl
Thus it is equal to 400 mOsm/L of glucose.
That means it is isosmatic with 400mOsm/L of glucose.
This option is given in option (E). Hence option (E) is the Answer.
Thus the Answer is option (E)
Let us check the other options:
it is given that it is hypoosmatic,in option (A) means less than 400 mOsm/L.
In option (D) it is given hyperosmatic to 200 mM KCl means greater than 400 mOSm/L
Hence option (A) and option (D) are not the Answer.
in option (B) it is given isosmatic to 600mM of KCl solution
600mM KCl solution = 2 x 600 mOsm/L = 1200 mOsm/L
This is not equal to 400 mOsm/L of glucose.
Hence option (B) cannot be the Answer.
In option (C) it is given isosmatic to 0.18% KCl solution
0.18% KCl solution means 0.18 g per 100 mL of solution
Or 1.8 g per L
1.8 / 54.5 moles/L
= 0.033 moles/L
= 33 mM
= 2 x 33 = 66 mOsm / L
This is not equal to 400 mOsm / L of glucose
Hence option C cannot be the answer