Question

In: Biology

Describe how would you prepare the GTE (50 mM Glucose, 20 mM Tris, EDTA) Resuspension Solution...

Describe how would you prepare the GTE (50 mM Glucose, 20 mM Tris, EDTA) Resuspension Solution for use in a mini-prep. You have the following stock solutions: 0.5 M glucose, 0.2 M Tris-HCl (pH 8.0), 0.5 M EDTA (pH 8.0).
How would you prepare 150 mL of GTE re-suspension solution using the above stocks?

Also, describe how to prepare the solution in appropriate container and aseptic technique.

Solutions

Expert Solution

Glucose-tris-EDTA (GTE) buffer is used during DNA extraction to resuspend cells before the cell lysis is carried out. The primary purpose of the GTE buffer is to ensure a homogenous solution of cells from which the DNA has to be extracted. A homogenous solution will ensure complete lysis of the cells while also providing a stable environment for the released DNA. Glucose in the GTE buffer maintains the osmolarity of the solution, tris(hydroxymethyl)aminomethane (tris) maintains the pH and EDTA prevents DNA degradation.

To prepare a working concentration of the GTE buffer, the following formula can be used.

V1 x C1 = V2 x C2

Where,

V1 = volume of stock solution

V2 = final volume of working solution

C1 = concentration of stock solution

C2 = concentration of working solution

We need 150ml of 50 mM Glucose, 20 mM Tris, 10 mM EDTA.

We have the following stock solutions

0.5 M glucose, 0.2 M Tris-HCl (pH 8.0), 0.5 M EDTA (pH 8.0).

1. Preparation of 50 mM glucose

V1 = has to be calculated

V2 = 150ml

C1 = 0.5M = 0.5 x 1000 = 500 mM

C2 = 50 mM

V1 x C1 = V2 x C2

V1 x 500 = 150 x 50

V1 = (150 x 50) / 500 = 7500 / 500 = 15 ml

15 ml of 0.5M glucose

2. Preparation of 20 mM Tris

V1 = has to be calculated

V2 = 150ml

C1 = 0.2M = 0.2 x 1000 = 200 mM

C2 = 20 mM

V1 x C1 = V2 x C2

V1 x 200 = 150 x 20

V1 = (150 x 20) / 200 = 3000 / 200 = 15 ml

15 ml of 0.2M Tris

3. Preparation of 10 mM EDTA

V1 = has to be calculated

V2 = 150ml

C1 = 0.5M = 0.5 x 1000 = 500 mM

C2 = 10 mM

V1 x C1 = V2 x C2

V1 x 500 = 150 x 10

V1 = (150 x 10) / 500 = 1500 / 500 = 3 ml

3 ml of 0.5M EDTA

Preparation of GTE (50 mM Glucose, 20 mM Tris, EDTA) Resuspension Solution

1. Take a sterile 500ml beaker.

2. Using a sterile pipette transfer 15 ml of 0.5M glucose to the beaker.

2. Using a fresh sterile pipette transfer 15 ml of 0.2M Tris to the same beaker.

3. Using a fresh sterile pipette transfer 3 ml of 0.5M EDTA to the same beaker.

4. Measure 117 ml of distilled water in a sterile cylinder and add to the same beaker.

5. Mix well


Related Solutions

How you would prepare a 500 mL solution of 0.1M "tris" buffer at pH of 7.5...
How you would prepare a 500 mL solution of 0.1M "tris" buffer at pH of 7.5 starting with solid tris free base. The free base has a chemical forumla of (HOCH2)3-C-NH2 and a MW of 121.1 g/mol. The protonated amine form, tris-chloride, has a pKa of 8.10. To prepare the solution, 1.0M HCl will be used.
How would you make up 100 ml of 50 mM Tris-HCl buffer at pH 7.4, using...
How would you make up 100 ml of 50 mM Tris-HCl buffer at pH 7.4, using the 0.5 M Tris base stock solution, and any other required materials?
Describe how to prepare for this desired Tris buffer: 500 ml of 2 M Tris-HCl buffer...
Describe how to prepare for this desired Tris buffer: 500 ml of 2 M Tris-HCl buffer with a pH of 9.2 . The molecular weight of Tris base is 121.14 g/mol.
describe how you would prepare 1.25L of a 0.025 M sucrose solution from a stock solution...
describe how you would prepare 1.25L of a 0.025 M sucrose solution from a stock solution with concentration of 5.00 M.
BUFFERS: (Final concentration for 1x is 20 mM Tris; 500 mM NaCl; 1 mM CaCl2; 1...
BUFFERS: (Final concentration for 1x is 20 mM Tris; 500 mM NaCl; 1 mM CaCl2; 1 mM MgCl2; pH 7.4) 5x ConA Buffer, (1L)     •       700 ml dH2O, set stirring and add:     •       100 ml 1M Tris, pH 7.2-7.4     •       5 ml 1M MgCl2     •       5 ml 1M CaCl2     •       146 g NaCl     •       Check pH is between 7.2 and 7.4     •       To 1000 ml with dH2O Elution Buffer A: ~0.2M AMM: 0.1...
Describe how you would prepare a liter aqueous solution of each of the following reagents (a)...
Describe how you would prepare a liter aqueous solution of each of the following reagents (a) 1 M glycine (b) 0.5 M glucose (c) 10 mM ethanol (d) 100 mM hemoglobin
Describe how to prepare 50 mL of solution buffered at pH 5.00. The buffer must be...
Describe how to prepare 50 mL of solution buffered at pH 5.00. The buffer must be designed so the pH changes no more than 0.10 units with the addition of 0.001 moles of acid or base. Choose from the following to design the buffer. Be sure to choose the buffer pair best suited to the assigned conditions. 1.acetic acid/sodium acetate 2.formic acid/sodium formate 3. benzoic acid/sodium benzoate please show your work-thank you!
A solution is prepared that contains 10 mM NaCl, 20 mM CaCl2, 20 mM BaCl2, and...
A solution is prepared that contains 10 mM NaCl, 20 mM CaCl2, 20 mM BaCl2, and 50 mM NiNO3. Of course, all these salts completely dissolve to their respective cations and anions. The pH is 7.0. (a) Calculate the ionic strength of the solution. (b) Calculate the activity coefficients for H+, Cl-, and Ba2+ (use the Guntenberg approximation because the solutions do, though note there are a few other equations and a graph that can be used at your discretion...
You prepare 50 mL of 50 mM HEPES buffer at pH 7.4. Indicate the amounts of...
You prepare 50 mL of 50 mM HEPES buffer at pH 7.4. Indicate the amounts of each of the following reagents you would use (if applicable)? HEPES ______(g); 10 M NaOH______(mL); 1 M HCl________(μL)
TAE buffer contains Tris base, acetic acid, and EDTA. Briefly describe what this buffer is used...
TAE buffer contains Tris base, acetic acid, and EDTA. Briefly describe what this buffer is used for and what are the specific functions of each component. Why is it important to use TAE buffer instead of water in situations in which TAE is recommended?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT