In: Chemistry
If the concentration of glucose inside an E. coli cell is 5.1 mM, how many glucose molecules are in the cell? Assume an E. coli cell to be a cylinder 1.9 micrometers long and 0.8 micrometers in diameter. Enter your answer to the nearest ones.
I thought it was 3.0*106 but it was wrong.
Answer – Given, concentration of glucose = 5.1 mM
cylinder 1.9 micrometers long and 0.8 micrometers in diameter
so , radius, r = 0.80 micrometers / 2 = 0.4 micrometers
we know
1 micrometers = 1.0*10-5 dm
So, 0.4 micrometers = ?
= 4.0*10-4 dm
And length , h = 1.9 micrometers = 1.9*10-5 dm
So, volume of coli cell
Volume , V = π*r2*h
= 3.14 * (4.0*10-4 dm)2 * 1.9*10-5 dm
= 9.55*10-12 dm3
We know, 1 dm3 = 1 L
So, molarity = moles/ L
So, moles = molarity * volume L
= 0.0051M * 9.55*10-12 L
= 4.87*10-14 moles
We know ,
1 mole = 6.023*1023 molecules
So, 4.87*10-14 moles = ?
= 2.93*1010 molecules