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A microscope with a tube length of 200 mm achieves a total magnification of 400
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A microscope with a tube length of 180 mm achieves a total magnification of 800\times with a 40x times objective and a 20x times eyepiece. The microscope is focused for viewing with a relaxed eye. How far is the sample from the objective lens?
Answer
The tube length is L = 180 mm
The total magnification is M = 800
The magnification of objective is Mo = 40
The magnification of eyepiece is Me = 20
Let the sample be at a distance p from the objective then
The distance of the image of the objective will be Io = MoP =
40P
This will be at L-40p from the eye piece
The distance of the image of the eyepiece will be Ie = Me(L-40P) =
20(L-40P)
The overall magnification
M = 20(L-40P)/P
800P = 20L - 800P
1600 P = 3600 mm
P = 2.25 mm