You have a symmetrical sag vertical curve of Length = 6 stations. The entering tangent from...

You have a symmetrical sag vertical curve of Length = 6 stations. The entering tangent from the left has a gradient of –6% and the exiting tangent has a gradient of +4%. The VPC Station has an elevation of 250.00 feet (which will be your C-Value) and its station distance is measured to be at 40+00 stations. You will now do the following:

Find the elevation and station of the VPI.

Find the elevation and station of the VPT

Find the elevations on the curve at every station from the VPC, ending at the VPT.

Confirm the station elevation at the VPT comparing the value you obtained from your curve computation with the value you obtained from the tangent gradient computation. Find the elevation and station of the low point on the curve.
If this is not possible, use your long form calculations with statements with what you are doing. JUST DON’T GIVE ME A BUNCH OF NUMBERS I CAN’T FOLLOW. Use a sheet of paper to you draw the diagram that will help you to follow through your calculations.

Expert Solution

Ally Wells answered 11 months ago

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