A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%....

A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%. What is the minimum length of the curve for acceptable passing sight distance at night, with headlight illumination? Express your answer in feet to five significant figures.

there is no more info. this is all that was given to us.

Expert Solution

Ally Wells answered 8 months ago

A grade g1=+2.00% intersects grade g2=−1.40% at a vertex whose station and elevation are 78+60 and...

A grade g1=+2.00% intersects grade g2=−1.40% at a vertex whose station and elevation are 78+60 and 7855.35 ft, respectively. An equal-tangent parabolic curve 505 ft long has been selected to join the two tangents. Compute station elevations for the curve, for stakeout at full stations.

Given the following vertical curve data: PVI at 19+ 00,L= 500 ft,g1= +2.5%,g2= -1%, and elevation...

Given the following vertical curve data: PVI at 19+ 00,L= 500 ft,g1= +2.5%,g2= -1%, and elevation of PVI = 723.86 ft.Compute the elevationsof the curve summit (i.e. high point)andfullstations.Assume that all symbols have their usual meaning.

Vertical Curves: Given g1 = -3%, g2 = 2%, L = 500', VPI Station of 100+00...

Vertical Curves: Given g1 = -3%, g2 = 2%, L = 500', VPI Station of 100+00 Calculate the PT Stationing.

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents...

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents intersect at sta. 38+60.24 and elevation 1,400.13 ft, develop an Excel spreadsheet to calculate the elevations of the grade line at each station from sta. 31+00 to 45+00. Include the elevations of the PVC and PVT.

4.2 A 200 m long sag curve is used under a grade separation structure. The curve...

4.2 A 200 m long sag curve is used under a grade separation structure. The curve joins an entry grade of - 3% and exit grade of + 5%. If the required vertical clearance is 5.5 m, determine the available sight distance over the curve. Assume driver eye height and dangerous object height of 1.8 m and 0.15, respectively. If the information available is not complete, please assume and specify a reasonable value and continue with the assignments.

A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...

A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its...

A vertical curve has an incoming grade of -3.2% and the exit grade is +2.2%. The...

A vertical curve has an incoming grade of -3.2% and the exit grade is +2.2%. The length of the curve is 800 ft. The stationing and elevation at the point of intersection of the grades are 73+22 and 1842.35 ft. Compute the curve and determine elevations on the curve at the +00 points. Then determine the elevation of the curve at the low point. If a sewer pipe is to pass underneath at the lowest point, what elevation should the...

A vertical sag curve connects two tangents with grades -3% and +2% with the design speed...

A vertical sag curve connects two tangents with grades -3% and +2% with the design speed of 100 km/h. (a) Calculate the available sight distance and the length of the vertical curve using the minimum flatness of curve that will satisfy the headlight criterion during dark conditions. Assume the height of the headlight above the pavement is 0.6 m and the angle of the light beam upward from the axis of beam is 1. (a) Assuming that the length of...

You have a symmetrical sag vertical curve of Length = 6 stations. The entering tangent from...

You have a symmetrical sag vertical curve of Length = 6 stations. The entering tangent from the left has a gradient of –6% and the exiting tangent has a gradient of +4%. The VPC Station has an elevation of 250.00 feet (which will be your C-Value) and its station distance is measured to be at 40+00 stations. You will now do the following: Find the elevation and station of the VPI. Find the elevation and station of the VPT Find...

A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and...

A 276 m equal-tangent sag vertical curve has the PVC at station 3 + 700.000 and elevation 321 m. The initial grade is -3.5% and the final grade is +0.5%. Determine the stationing and elevation of the PVI, the PVT, and the lowest point on the curve.

Question