Find the following probabilities for the standard normal random variable z: (a) P(−0.76<z<0.75)= (b) P(−0.98<z<1.36)= (c)...

Find the following probabilities for the standard normal random variable z:

(a) P(−0.76<z<0.75)=

(b) P(−0.98<z<1.36)=

(c) P(z<1.94)=

(d) P(z>−1.2)=

2.

Suppose the scores of students on an exam are Normally distributed with a mean of 480 and a standard deviation of 59. Then approximately 99.7% of the exam scores lie between the numbers ---- and -----. ??

Hint: You do not need to use table E for this problem.

Expert Solution

OR by using excel we can get it directly :

using excel :

milcah answered 1 month ago

Find the following probabilities for the standard normal random variable z z : a) P(−2.07≤z≤1.93)= P...

Find the following probabilities for the standard normal random variable z z : a) P(−2.07≤z≤1.93)= P ( − 2.07 ≤ z ≤ 1.93 ) = (b) P(−0.46≤z≤1.73)= P ( − 0.46 ≤ z ≤ 1.73 ) = (c) P(z≤1.44)= P ( z ≤ 1.44 ) = (d) P(z>−1.57)= P ( z > − 1.57 ) =

) Find the following probabilities for the standard normal random variable zz: (a) P(−2≤z≤2.01)= (b) P(−0.5≤z≤1.62)= (c) P(z≤1.3)= (d) P(z>−1.1)=

1. If Z is a standard normal random variable, find c such that P(−c ≤ Z...

1. If Z is a standard normal random variable, find c such that P(−c ≤ Z ≤ c) = 0.82. [Answer to 2 decimal places] 2. Weakly earnings on a certain import venture are approximately normally distributed with a known mean of $353 and unknown standard deviation. If the proportion of earnings over $386 is 25%, find the standard deviation. Answer only up to two digits after decimal. 3. X is a normal random variable with mean μ and standard...

Given that z is a standard normal random variable, compute the following probabilities. P(z ≤ -0.71)...

Given that z is a standard normal random variable, compute the following probabilities. P(z ≤ -0.71) P(z ≤ 1.82) P(z ≥ -0.71) P(z ≥ 1.22) P( –1.71 ≤ z ≤ 2.88) P( 0.56 ≤ z ≤ 1.07) P( –1.65 ≤ z ≤ –1.65) Given that z is a standard normal random variable, find z, for each situation. The area to the left of z is 0.9608 The area to the right of z is .0102 The area between o and...

If Z is a standard normal random variable, find the value z0 for the following probabilities....

If Z is a standard normal random variable, find the value z0 for the following probabilities. (Round your answers to two decimal places.) (a) P(Z > z0) = 0.5 z0 = (b) P(Z < z0) = 0.9279 z0 = (c) P(−z0 < Z < z0) = 0.90 z0 = (d) P(−z0 < Z < z0) = 0.99 z0 =

Find the probabilities for the standard normal random variable z: (1 point) P(-2.58<z<2.58) x is a...

Find the probabilities for the standard normal random variable z: (1 point) P(-2.58<z<2.58) x is a normal random variable with mean (μ) of 10 and standard deviation (σ) of 2. Find the following probabilities: (4 points) P(x>13.5) (1 point) P(x<13.5) (1 point) P(9.4<x<10.6) (2 points)

(1 point) Find the following probabilities for the standard normal random variable ?z: (a) ?(−0.84≤?≤0.2)= (b) ?(−2.16≤?≤1.12)= (c) ?(?≤0.31)=...

(1 point) Find the following probabilities for the standard normal random variable ?z: (a) ?(−0.84≤?≤0.2)= (b) ?(−2.16≤?≤1.12)= (c) ?(?≤0.31)= (d) ?(?>−0.95)=

Find the following probability for a standard normal random variable, P(Z ≥ -2.16 )

Find the following probabilities for a standard normal random variable Z. Note: Round your answers to...

Find the following probabilities for a standard normal random variable Z. Note: Round your answers to four decimal places. A) P(Z < -1.47) B) P(Z > 2.20) C) P(Z > -1.17) D) P(Z < 1.30)

Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z|...

Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z| <A)= 0.95 This is what I have: P(-A<Z<A) = 0.95 -A = -1.96 How do I use the symmetric property of normal distribution to make A = 1.96? My answer at the moment is P(|z|< (-1.96) = 0.95

Question