Suppose you gather a sample size of 20 widgets and construct a
99% confidence interval for the mean number of widgets.
Assuming this research follows approximately normal with unknown
mean and variance, what would be the value of the distribution
percentage point that I would use when constructing this
interval?
Thanks for answering!
find the sample size needed to give with 99%
confidence a margin of error of plus or minus 5% when estimating
proportion within plus minus 4% within plus minus 1%
The 99% confidence interval for the mean, calculated from a
sample of size n = 10 is 0.9390859 ≤ μ ≤ 5.460914 . Determine the
sample mean X ¯ = (round to the first decimal place). Assuming that
the data is normally distributed, determine the sample standard
deviation s = (round to the first decimal place)
Compute the 99% confidence interval estimate for the population
proportion, p, based on a sample size of 100 when the sample
proportion, p (overbar), is equal to 0.26
Given a random sample of size 322. Find a 99% confidence
interval for the population proportion if the number of successes
was 168.
(Use 3 decimal places.)
lower limit
upper limit
Determine the sample size n needed to construct a 99%
confidence interval to estimate the population proportion when p
over bar equals 0.62 and the margin of error equals 7%.
n=?????