In: Statistics and Probability
SOLUTION:
From given data,
What sample size would be needed to construct a 95% confidence interval with a 3% margin of error on any population proportion
In this problem , we do not have prior information about the proportion.
Let
Confidence level = 95% ,
Desired Margin of Error = E = 3% = 3/100 = 0.03
Note : Margin of Error = (Length of CI) /2
Since we don't have preliminary estimate,
we use = 0.5 which requires the maximum n
95% confidence interval
Confidence interval is 95%
95% = 95/100 = 0.95
Significance level = = 1 - Confidence interval = 1-0.95 = 0.05
/2 = 0.05 / 2
= 0.025
The Critical Value = Z/2 = Z0.025 = 1.96 (From z table)
Sample size
n = (1- ) (Z/2 / E)2
n = 0.5 (1- 0.5) (1.96 / 0.03)2
n = 0.5 0.5 (65.33333)2
n = 0.5 0.5 4268.4440
n = 1067.111
Since the minimum n has to be integer , we take the ceiling of above number and get n= 1067
Sample Size should be atleast n =1067