Find the pH of a 0.170M HClO2(aq) solution. For HClO2, Ka=0.011.

Expert Solution

For the given reaction -

HClO₂ (aq) + H₂O (l) <------------> H₃O⁺ (aq) + ClO₂^- (aq)

I(M) 0.170 - 0 0

C -x +x +x

Eq (0.170-x) x x

Therefore -

K_a = 0.011 = (x)(x) / (0.170-x)

By solving the above equation - x = 0.038 M

Hence - x = [H₃O⁺] = 0.038 M

Therefore - pH = - log [H₃O⁺] = - log(0.038) = 1.41

queen_honey_blossom answered 11 months ago

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