1. Radios often utilize a variable capacitor (capacitance is changed by either changing the distance between...

1. Radios often utilize a variable capacitor (capacitance is changed by either changing the distance between plates or amount of dielectric between plates) in series with an inductor to tune the circuit to a particular frequency. In a particular shortwave radio, the value of the inductor is $L=1.09 \mu H .$ What must be the capacitance (in $\mathrm{pF}$ ) of the circuit so that the radio is tuned to a frequency of $\mathrm{f}=6.95 \mathrm{MHz}$ ?

2. A conducting coil, with current $i(t)=4.20 * e^{0.0250 t} \sin (120 \pi t)$ , with i in amperes and $t$ in seconds, is placed next to a second coil, end to end. At $\mathrm{t}=0.740 \mathrm{~s}$ , a. lab tech measures the emf across the second coil, and the result is $\mathscr{E}=-3.70 \mathrm{~V} .$ What is the mutual inductance (in $\mathrm{mH}$ ) of the coils?

Expert Solution

genius_generous answered 2 years ago

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