In: Chemistry
The enzyme is studied in the presence of a different inhibitor (inhibitor B). In this case, two different concentrations of inhibitor are used. Data are as follows:
a) Determine the apparent Vmax at each inhibitor concentration.
b) Determine the apparent KM at each inhibitor concentration.
c) Estimate KI from these data. [Hint: Calculate the KI at 3 mM and at 5 mM; and then take the average of the two KI values.]
| v[(mmol/L)min−1] | |||
| [S](mmol/L) | No inhibitor | 3 mM inhibitor B | 5 mM inhibitor B | 
| 1.25 | 1.72 | 1.25 | 1.01 | 
| 1.67 | 2.04 | 1.54 | 1.26 | 
| 2.50 | 2.63 | 2.00 | 1.72 | 
| 5.00 | 3.33 | 2.86 | 2.56 | 
| 10.00 | 4.17 | 3.70 | 3.49 |