In: Civil Engineering
The 45∘ strain rosette is mounted on the surface of a shell. The
following readings are obtained for each gage: ϵa=−200(10−6),
ϵb=300(10−6), and ϵc=250(10−6)
Determine the in-plane principal strains
Ans) Gicen,
a = -200 x 10^(-6)
b = 300 x 10^(-6)
c = 250 x 10^(-6)
Since, the rosette is arranged at 45 degree,
x = a
y = c
xy = 2b - (a + c)
Putting given values,
x = a = -200 x 10^(-6)
y = c = 250 x 10^(-6)
xy = 2b - (a + c) = 2(300) x 10^(-6) - ((-200 + 250) x 10^(-6)) = 550 x 10^(-6)
Now,
tan 2 = xy / (x - y)
=> tan 2 = 550 / (-200 - 250) = -1.222
=> 2 = arctan(-1.222) = -50.70 degree
=> = -25.35 degree
Hence, ' = 90 + = 90 - 25.35 = 64.65 degree
Also,
= [(x + y) / 2] + [(x - y) /2] Cos 2 + (xy/2)Sin 2
Putting values,
=> = [(-200 + 250) / 2 + [(-200 - 250)/2] Cos(-50.70) + (550/2)Sin(-50.70)] x 10^(-6)
=> = (25 + 142.51 - 212.80) x 10^(-6)
=> = -45.29 x 10^(-6)
Now, ' = x + y -
=> ' = (-200 + 250 - (-45.29)) x 10^(-6)
=> ' = 95.29 x 10^(-6)