In: Physics
Consider a spherical shell with radius R and surface charge density σ. By integrating the electric field, find the potential outside and inside the shell. You should find that the potential is constant inside the shell. Why?
Electric field inside the shell is zero, as there is no enclosed
charge inside and due to spherical symmetry from the Gauss's law we
get that E is zero inside. And the electric field is otside r>R
is
So, the potential outside the shell is
And the potential inside
(As E is zero inside, so the 2nd term vanishes).
So, the potential is constant inside the shell. This is obvious
from the fact that the elctric field is zero everywhere inside the
spherical shell. This is also true from the fact that from
Laplace's equation, we have the result that the potential function
V(r) is extremum at the boundary. i.e, the maximum and minimum both
are at the boundary. As the value of the function V(r) is constant
at the boundary r = R. So, this is the minimum and maximum also for
the solution of the Laplace's equation inside the sphere. So, the
solution V(r) has to be a constant and its value inside is the same
as its value at the boundary.