Question

In: Statistics and Probability

A poultry producer is interested in which feed type will yield the poultry weight. He has...

A poultry producer is interested in which feed type will yield the poultry weight. He has two types of feed; the first made from soybeans and the second made from sunflower seeds. He has 71 chickens and randomly selects 26 of these chickens to use in his experiment. 14 of these chickens are randomly assigned to receive only the soybean product and the remaining 12 are to receive only the sunflower product. Is there a difference in these weights at a ten percent error rate? Estimate the mean difference in the weights of these chickens using 90% confidence. The data are below.

Soybean Feed 199.86 237.32 335.21 203.80 166.66 340.68 234.31 254.03 296.78 289.57 246.15 247.51 125.27 296.90

Sunflower Feed 279.04 247.33 362.32 262.55 305.91 295.22 335.41 292.62 336.80 307.60 307.67 317.60

Soybean Feed

n1 = 10
x̄1 = 0.022

s1 = 0.159

Sunflower Feed

n2 = 13
x̄2 = 0.008

s2 = 0.008

Solutions

Expert Solution

Soybean Feed ( X ) Sunflower Feed ( Y )
199.86 2331.5764 279.04 631.6426
237.32 117.2109 247.33 3231.0698
335.21 7580.0704 362.32 3381.1318
203.8 1966.6032 262.55 1732.4325
166.66 6640.0334 305.91 3.0189
340.68 8562.4671 295.22 80.1473
234.31 191.446 335.41 975.7814
254.03 34.6167 292.62 133.4603
296.78 2365.227 336.8 1064.5538
289.57 1715.9146 307.6 11.7478
246.15 3.9856 307.67 12.2325
247.51 0.405 317.6 180.2978
125.3 15098.6097
296.9 2376.9135
Total 3474.05 48985.0795 3650.07 11437.5165

Mean

Standard deviation

Mean

Standard deviation

To Test :-

H0 :-

H1 :-  

Test Statistic :-
t = (\bar{X_{1}} - \bar{X_{2}}) / \sqrt{ ( S_{1}^{2} / n1) + (S_{2}^{2} / n2)}
t = ( 248.1464 - 304.1725 ) / \sqrt{ ( 61.3847^{2} / 14) + ( 32.2455^{2} / 12)}
t = -2.9702


Test Criteria :-
Reject null hypothesis if




DF = 20




Result :- Reject Null Hypothesis


Decision based on P value
P - value = P ( t > 2.9702 ) = 0.0076
Reject null hypothesis if P value <    level of significance
P - value = 0.0076 < 0.1 ,hence we reject null hypothesis
Conclusion :- Reject null hypothesis

There is sufficient evidence to support the claim that there is difference in average  poultry weight at 10% level of significance.

Confidence interval :-



Lower Limit =
Lower Limit = -88.5587
Upper Limit =
Upper Limit = -23.4935
90% Confidence interval is ( -88.5587 , -23.4935 )


Related Solutions

A poultry farmer using a certain type of feed in his chickens achieves an average weight...
A poultry farmer using a certain type of feed in his chickens achieves an average weight of 1.65kgs in six weeks with a standard deviation of 2kgs for a sample of 56 chickens . he suspects the feed and does the experiment on 60 chickens on a different feed and achieves an average weight of 1.7kgs in six weeks when the standard deviation is 3. Are the two feed types significantly different?. test at 5% significance level. Kindly show all...
a) Ghana Agro Food Processing Company Limited has spare capacity to process poultry feed and is...
a) Ghana Agro Food Processing Company Limited has spare capacity to process poultry feed and is considering offering a service to the Greater Accra Poultry Farmers Association. To aid deliberations concerned with what rate should be quoted when offering the service, the Poultry Manager has asked for your assistance in analysing the Poultry department’s fixed and variable costs. From her departmental records, the poultry manager has extracted the following schedule of cost information. Month poultry costs Metric tons (MT) of...
Dwight Schrute is interested in the weight of a single sheet of paper. He measures 15...
Dwight Schrute is interested in the weight of a single sheet of paper. He measures 15 pieces of paper and finds the sample standard deviation to be 0.0083 grams. He would like to test whether or not the standard deviation differs from 0.01 grams. Use a=0.05. What is the 95% confidence interval?
Dwight Schrute is interested in the weight of a single sheet of paper. He measures 15...
Dwight Schrute is interested in the weight of a single sheet of paper. He measures 15 pieces of paper and finds the sample standard deviation to be 0.0083 grams. He would like to test whether or not the standard deviation differs from 0.01 grams. Use a=0.05. What is the 95% confidence interval?
A producer of cereal measures part of its product quality by measuring box weight. It has...
A producer of cereal measures part of its product quality by measuring box weight. It has established that each box should be 475 grams ± 5 grams. When the production was known to be under control, it obtained samples of 5 boxes and measured their weight. It then calculated the sample range R and sample mean x¯ (x bar). It then calculated the average of the ranges as R¯ = 5.5 grams and the average of the sample means as...
A contractor is interested in the total cost of a project for which he intends to...
A contractor is interested in the total cost of a project for which he intends to bid. He estimates that materials will cost P25000 and that his labour will cost P900 per day. The contractor then formulates the probability distribution for completion time (X), in days, as given in the following table. Completion time in days (X) 10 11 12 13 14 P(X=x) 0.1 0.3 0.3 0.2 0.1 a) Determine the total cost function C for the project. b) Find...
Question 1 A contractor is interested in the total cost of a project for which he...
Question 1 A contractor is interested in the total cost of a project for which he intends to bid. He estimates that materials will cost P25000 and that his labour will cost P900 per day. The contractor then formulates the probability distribution for completion time (X), in days, as given in the following table. Completion time in days (X) 10 11 12 13 14 P(X=x) 0.1 0.3 0.3 0.2 0.1 a) Determine the total cost function C for the project....
A farmer needs to decide which type of corn he wants to plant. To decide, he...
A farmer needs to decide which type of corn he wants to plant. To decide, he plants two small test areas. After the corn has grown he compares the lengths of the cobs. He looks at 35 cobs of Type A, which had an average length of 6.3 inches with a variance of 1. He looks at 30 cobs of Type B, which had an average length of 5.9 with a variance of 1.3. Calculate a 95% confidence interval for...
Alex is an employee at Big Country Producer Pty Ltd. He has negotiated the following remuneration...
Alex is an employee at Big Country Producer Pty Ltd. He has negotiated the following remuneration package: •        Cash salary of $200,000. •        On July 1, 2018 Alex was given a loan of $15,000 which he used to pay for an overseas holiday for her family. The loan is expected to be repaid over 3 years with an instalment of $5,000 due on June 30, 2019, 2020, and 2021. There is no interest charged on the loan. •        Payment of his health club...
he weight of an organ in adult males has a​ bell-shaped distribution with a mean of...
he weight of an organ in adult males has a​ bell-shaped distribution with a mean of 320 grams and a standard deviation of 30 grams. Use the empirical rule to determine the following. ​(a) About 68​% of organs will be between what​ weights? ​(b) What percentage of organs weighs between 230 grams and 410 ​grams? ​(c) What percentage of organs weighs less than 230 grams or more than 410 ​grams? ​(d) What percentage of organs weighs between 260 grams and...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT