In: Chemistry
Calculate the change in molar Gibbs energy of carbon dioxide (treated as a perfect gas) at 20°C when its pressure is changed isothermally from 1.0 bar to (a) 2.0 bar, (b) 0.00027 atm, its partial pressure in air.
Solution : Calculate the change in molar Gibbs energy of carbon dioxide
a. From 1.0 bar to 2.0 bar
By the formula ΔGm = RT ln(Pf/Pi) (perfect gas).
Parameter | Value |
---|---|
R | 8.314 J/molK |
T | 293 K |
Pf | 2.0 bar = 2 x 105 Pa |
Pi | 1.0 bar = 1 x 105 Pa |
Then ΔGm = 8.314 x 293 x ln(2 x 105/1 x 105) = 1680.84 J/mol
Therefore, The change in molar Gibbs energy is | ΔGm = 1680.84 J/mol |
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b. From 1 bar to 0.00027 atm
From the formula ΔGm = RT ln(Pf/Pi) (perfect gas).
Parameter | Value |
---|---|
R | 8.314 J/molK |
T | 293 K |
Pf | 0.00027 atm = 25 Pa |
Pi | 1.0 bar = 105 Pa |
Then ΔGm = 8.314 x 293 x ln(25/105) = -4165.56 J/mol
Therefore, The change in molar Gibbs energy is | ΔGm = -4165.56 J/mol |
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a. Therefore, ΔGm = 1680.84 J/mol
b. Therefore, ΔGm = -4165.56 J/mol