In: Chemistry
Calculate the voltage of the following cell at nonstandard conditions:
Cu | Cu2+ (0.150 M) || Cu2+ (.0120 M) | Cu
Convert your final answer to mV.
Group of answer choices
64.9 mV
-32.4 mV
-16.2 mV
32.4 mV
Cu(s) -------------> Cu^2+ (aq) + 2e^- E0 = -0.34v
Cu^2+ (aq) + 2e^- -------> Cu(s) E0 = 0.34v
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Cu(s) + Cu^2+(aq) ------> Cu^2+(aq) + Cu(s) E0cell = 0
n = 2
Ecell = E0cell - 0.0592/n logQ
= 0 -0.0592/2log[Cu^2+]/[Cu^2+]
= -0.0296log0.15/0.012
= -0.0296*1.0969
= -0.0324v
= -32.4mv >>>>answer