Question

In: Chemistry

Calculate the voltage of the following cell at nonstandard conditions: Cu | Cu2+ (0.150 M) ||...

Calculate the voltage of the following cell at nonstandard conditions:

Cu | Cu2+ (0.150 M) || Cu2+ (.0120 M) | Cu

Convert your final answer to mV.

Group of answer choices

64.9 mV

-32.4 mV

-16.2 mV

32.4 mV

Solutions

Expert Solution

Cu(s) -------------> Cu^2+ (aq) + 2e^-        E0 = -0.34v

Cu^2+ (aq) + 2e^- -------> Cu(s)              E0 = 0.34v

-------------------------------------------------------------------------

Cu(s) + Cu^2+(aq) ------> Cu^2+(aq) + Cu(s)             E0cell = 0

n = 2

Ecell   = E0cell - 0.0592/n logQ

           = 0 -0.0592/2log[Cu^2+]/[Cu^2+]

           = -0.0296log0.15/0.012

           = -0.0296*1.0969

             = -0.0324v

            = -32.4mv   >>>>answer


Related Solutions

Calculate the cell potential for the following electrochemical cell: Zn | [Zn2+]=4.2M || [Cu2+]=0.004M | Cu
Calculate the cell potential for the following electrochemical cell: Zn | [Zn2+]=4.2M || [Cu2+]=0.004M | Cu  
A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu2+ salt...
A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu2+ salt and the other half-cell with a Cd bar in the same volume of a 1.00 M Cd2+ salt. (a) Find E o cell , ΔG o , and K. Report your answers to the correct number of significant figures. E o cell = V ΔG o = × 10 J K = × 10 (b) As the cell operates, [Cd2+] increases; find E cell...
A Cu/Cu2+ concentration cell (E∘=0.34V) has a voltage of 0.23 V at 25 ∘C. The concentration...
A Cu/Cu2+ concentration cell (E∘=0.34V) has a voltage of 0.23 V at 25 ∘C. The concentration of Cu2+ in the cathode is 1.6×10−3 molL−1. Part A What is the concentration of Cu2+ in anode?
The following takes place in a voltaic cell: Zn(s) + Cu2+(1 M) → Cu(s) + Zn2+(1...
The following takes place in a voltaic cell: Zn(s) + Cu2+(1 M) → Cu(s) + Zn2+(1 M). The cell has a voltage of +1.10 V. Choose the answer that best relates to questions 1-4. (A) there is no change in the voltage (B) the voltage becomes zero (C) the voltage increases (D) the voltage decreases, but stays positive (E) the voltage becomes negative 1. What happens to the voltage when a saturated ZnSO4 solution is added to the zinc compartment...
What is the cell potential (emf, in V) of this cell at 25oC? Cu |Cu2+ (0.0296...
What is the cell potential (emf, in V) of this cell at 25oC? Cu |Cu2+ (0.0296 M) ǁ Br2 |Br- (0.364 M)
1A: Calculate E for the cell Cu(s)+2Ag+(aq)--->Cu+2(aq)+2Ag(s) at 298K when [Ag+]=0.025M and [Cu2+]=0.068 M 1B: Consider...
1A: Calculate E for the cell Cu(s)+2Ag+(aq)--->Cu+2(aq)+2Ag(s) at 298K when [Ag+]=0.025M and [Cu2+]=0.068 M 1B: Consider the cell Cd(s)+Cu2+(aq)-->Cu(s)+Cd2+. Calculate K for this reaction.
A voltaic cell consists of a Pb/Pb2+ half cell and a Cu/Cu2+ half cell at 25C....
A voltaic cell consists of a Pb/Pb2+ half cell and a Cu/Cu2+ half cell at 25C. The initial concentrations of Pb2+ and Cu2+ are 0.0520 M and 0.150 M respectively. Part A: What is the initial cell potential *Write answer using two significant figures Part B: What is the cell potential when the concentration of Cu2+ has fallen to 0.210 M *Write answer using three significant figures Part C: What is the concentration of Pb2+ when the cell potential falls...
Consider a cell based on the following line notation at 298 K: Cu | Cu2+ (0.237...
Consider a cell based on the following line notation at 298 K: Cu | Cu2+ (0.237 M) || Ni2+ (1.29 M) | Ni Given: Cu2+ + 2 e- → Cu     Eo = 0.34 V Ni2+ + 2 e- → Ni     Eo = -0.23 V How many of the following responses are true? 1. Decreasing the concentration of the Cu2+ will increase the concentration of the reaction 2. Using a Pt electrode in place of the Cu electrode will not change the potential...
A) Sketch the electrochemical cell made from Cu/Cu2+ and Ag/Ag+ half cells under standard conditions. (E0red...
A) Sketch the electrochemical cell made from Cu/Cu2+ and Ag/Ag+ half cells under standard conditions. (E0red (Ag+) = 0.80 V and E0red (Cu2+) = 0.34V) B) Towards which half-cell do electrons flow in the external circuit? C) In which half-cell does reduction occur? D) Calculate E0cell in volts (show work). E) Which electrode is the positive pole? F) Which electrode decreases in mass during cell operation. G) Which electrodes are considered active? H) What differences, if any, in responses B,...
A galvanic cell is set up as follows: Zn|Zn2+(0.01 mol/L)||Cu2+(0.1 mol/L)|Cu. How will the voltage of...
A galvanic cell is set up as follows: Zn|Zn2+(0.01 mol/L)||Cu2+(0.1 mol/L)|Cu. How will the voltage of the cell be affected by each of the following change: (a) increase Cu+2 concentration to 1mol/L; (b) decrease Zn2+ concentration to 0.0001 mol/L;
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT