For the balanced equation shown below, if 98.0 grams of C2H3Br3 were reacted with 62.2 grams...

For the balanced equation shown below, if 98.0 grams of C2H3Br3 were reacted with 62.2 grams of O2, how many grams of Br2 would be produced? 4C2H3Br3+11O2=8CO2+6H2P+6Br2

Expert Solution

4C2H3Br3 + 11O2 ---------------------------> 8CO2 + 6H2P + 6Br2

1066.8 g 352 g 479.4g

98.0 g 62.2 g ?

1066.8 g C2H3Br3 -----------------------> 352 g O2

98 .0 g C2H3Br3 -------------------------> 352 x 98 / 1066.8 = 32.33 g O2

we need only 32.33 g O2 . but we have 62.2 g O2 so it is excess reagent .

so limiting regaent is C2H3Br2.

1066.8 g C2H3Br3 --------------------------> 479.4 g Br2

98 g C2H3Br3 -------------------------------> 479.4 x 98 / 1066.8 = 44.0 g

mass of Br2 formed = 44.0 g

queen_honey_blossom answered 1 year ago

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