Question

In: Chemistry

When the half reaction shown below is balanced, the sum of the stoichiometricc coefficients is: __e–...

When the half reaction shown below is balanced, the sum of the stoichiometricc coefficients is: __e– +__H+(aq) +__Cr2O72–(aq)  __Cr3+(aq) +__H2O(l)

A. 24

B. 23

C. 10

D. 30

E. 15

Expert Solution

Given Equation:

__e^– +__H⁺_(aq) +__Cr₂O₇^2–_(aq)-----> __Cr³⁺_(aq) +__H₂O_(l)

1) Balance Chromium:

__Cr₂O₇^2–_(aq)-----> __Cr³⁺_(aq)

Cr₂O₇^2–_(aq)-----> 2Cr³⁺_(aq)

2) Balance Oxygen:

__Cr₂O₇^2–_(aq)-----> __Cr³⁺_(aq) +__H₂O_(l)

Cr₂O₇^2–_(aq)-----> 2Cr³⁺_(aq) + 7H₂O_(l)

3) Balance Hydrogen:

__H⁺_(aq) +__Cr₂O₇^2–_(aq)-----> __Cr³⁺_(aq) +__H₂O_(l)

14H⁺_(aq) + Cr₂O₇^2–_(aq)-----> 2Cr³⁺_(aq) + 7H₂O_(l)

4) Balance Charge:

__e^– +__H⁺_(aq) +__Cr₂O₇^2–_(aq)-----> __Cr³⁺_(aq) +__H₂O_(l)

6e^– + 14H⁺_(aq) + Cr₂O₇^2–_(aq)-----> 2Cr³⁺_(aq) + 7H₂O_(l)

Therefore, the sum of the stoichiometric coefficients are: 6 + 14 + 1 + 2 + 7 = 30

Answer: D. 30

queen_honey_blossom answered 2 years ago

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