In: Chemistry
Calculate the equilibrium 135I concentration and the equilibrium 135Xe for 3.0 w/o enriched fuel in a reactor that operates with a thermal neutron flux of 1 x 1013/(cm2*s). Use the value of Σf = 3.
Please explain your work!
For xenon-135 to be in equilibrium, iodine-135 must also be in equilibrium. Substituting the expression for equilibrium iodine-135 concentration into the equation for equilibrium xenon results in the following
Nxe (eq) = ( Yxe + Yi) Ef φ / ( λxe + σaXeφ)
Where Nxe = 135Xe concentration
γXe = fission yield of 135Xe
Ef = macroscopic fission cross section of the fuel
φ = thermal neutron flux
λxe = decay constant for 135Xe
Now for easy solution we can directly find equilibrium iodine-135 concentration & equilibrium xenon concentration from given here graph
so fom graph
equilibrium iodine-135 concentration = 8 x 1015 (Atom / cm3)
equilibrium xenon concentration = 7 x 1015 (Atom / cm3)