Calculate the equilibrium 135I concentration and the equilibrium 135Xe for 3.0 w/o enriched fuel in a...

Calculate the equilibrium ¹³⁵I concentration and the equilibrium ¹³⁵Xe for 3.0 w/o enriched fuel in a reactor that operates with a thermal neutron flux of 1 x 10¹³/(cm²*s). Use the value of Σ_f = 3.

Please explain your work!

Solutions

Expert Solution

For xenon-135 to be in equilibrium, iodine-135 must also be in equilibrium. Substituting the expression for equilibrium iodine-135 concentration into the equation for equilibrium xenon results in the following

Nxe (eq) = ( Y_xe + Y_i) E_f φ / ( λ_xe + σ_a^Xeφ)

Where Nxe = 135Xe concentration

γ_Xe = fission yield of 135Xe

Ef = macroscopic fission cross section of the fuel

φ = thermal neutron flux

λ_xe = decay constant for 135Xe

Now for easy solution we can directly find equilibrium iodine-135 concentration & equilibrium xenon concentration from given here graph

so fom graph

equilibrium iodine-135 concentration = 8 x 10¹⁵ (Atom / cm3)

equilibrium xenon concentration = 7 x 10¹⁵ (Atom / cm3)

queen_honey_blossom answered 7 months ago

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