In: Chemistry
Use the References to access important values if needed for this question. A sample of krypton gas occupies a volume of 7.59 L at 54 °C and 396 torr. If the volume of the gas sample is decreased to 6.16 L, while its temperature is increased to 117 °C, the resulting gas pressure will be __torr.
initial final
P1 = 396torr P2 =
T1 = 54+273 = 327K T2 = 117+273 = 390K
V1 = 7.59L V2 = 6.16L
P1V1/T1 = P2V2/T2
P2 = P1V1T2/T1V2
= 396*7.59*390/327*6.16 = 581.93torr >>>>answer