1. Use long division to convert decimal fraction into a binary
expansion. 3/5
2. Find the decimal equivalent for the following binary numbers.
1101.11102
3. Use long division to convert decimal fraction into a binary
expansion. 3/4
4. Find the binary equivalent the following decimal numbers. 14.
25390625 1
5. Find the decimal equivalent for the following binary numbers.
0.110001102
6. Exactly how many bytes are in the following? 60MB
Convert decimal +47 and +31 to binary, using the
signed-2’s-complement representation and enough digits to
accommodate the numbers. Then perform the binary equivalent of
(+31)+(-47), (-31)+(+47), and (-31)+(-47). Convert the answers back
to decimal and verify that they are correct.
1) Convert negative fractional decimal
number to 8-bit binary number: –
16.625 (use 2's complement binary format)
Hint: –17 + 0.375
Given the hint above, the fractional number will be divided into
two parts,
- Whole number,
- Fractional part, must be positive
(2) Proof to check that your calculation above
is correct
1. Convert to binary and hexadecimal (PLEASE SHOW
WORK)
a. 35
- binary:
- hexadecimal:
b. 85
- binary:
- hexadecimal:
c. 128
- binary:
- hexadecimal:
d. 4563
- binary:
- hexadecimal:
2. Convert the following decimal fractions to binary with a
maximum of six places to the right of the binary point: [12]
a. 25.84375 b. 57.55 c. 80.90625 d. 84.874023
1) Convert (0.513)10 to octal.
2) Given the two binary numbers X = 1010100 and Y = 1000011,
perform the subtraction (a) X - Y and (b) Y - X by using 2’s
complements.
4) Simplify the Boolean function and draw the logic diagram to
implement the function (i) F(a,b,c,d) = ∑(0,1,9,12,13,14) (ii)
F(a,b,c,d) = ∑(0,2,3,5,9,10,15) with don’t care d(a,b,c,d) =
∑(1,3,7,8,11,)
5) Implement the Boolean expression F (A, B, C, D) = _(1, 3,
4,7, 8,12, 13, 14, 15)...
Binary
How is 00001001 (base 2) represented in 8-bit two’s complement
notation?
Convert 0.3828125 to binary with 4 bits to the right of the binary
point.
How is 00110100 (base 2) represented in 8-bit one's
complement.