1. Pumping Lemma: a. Is the following language a regular language? (Use pumping lemma in proof.)...

1. Pumping Lemma:

a. Is the following language a regular language? (Use pumping lemma in proof.) L = {0n 1n 2n | n ≥ 0}

b. What is (i.e., define) the CFL pumping lemma?

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venereology answered 1 year ago

Use the pumping lemma to show that the following languages are not regular. A a. A1={0^n...

Use the pumping lemma to show that the following languages are not regular. A a. A1={0^n 1^n 2^n | n≥0} b. A2 = {www | w ∈ {a,b}∗} A c. A3 ={a^2^n | n≥0} (Here, a^2^n means a string of 2^n a’s.) A ={a3n |n > 0 }

Use the pumping lemma to show that the following languages are not regular (c) (5 pts)...

Use the pumping lemma to show that the following languages are not regular (c) (5 pts) Let Σ = {0, 1, −, =} and SUB = {x = y − z | x, y, z are binary integers, and x is the result of the subtraction of z from y}. For example: 1 = 1 − 0, 10 = 11 − 01 are strings in SUB but not 1 = 1 − 1 or 11 = 11 − 10.

Do not use Pumping Lemma for Regular Expression to prove the following. You may think of...

Do not use Pumping Lemma for Regular Expression to prove the following. You may think of Closure Properties of Regular Languages 1. Fix an alphabet. For any string w with |w| ≥ 2, let middle(w) be the string obtained by removing the first and last symbols of w. That is, Given L, a regular language on Σ, prove that f1(L) is regular, where f1(L) = {w : middle(w) ∈ L}

Prove that {anbamba2m+n:n,m≥1} is not regular using pumping lemma

Using the pumping lemma, prove that the language {1^n | n is a prime number} is...

Using the pumping lemma, prove that the language {1^n | n is a prime number} is not regular.

let sigma = {a,b,c}. Use the Pumping Lemma to show that the language L defined below...

let sigma = {a,b,c}. Use the Pumping Lemma to show that the language L defined below is not regular. L={ a^p c(bb)^q : q > p >1}

Regular => Context-Free Give a proof by induction on regular expressions that: For any language A,...

Regular => Context-Free Give a proof by induction on regular expressions that: For any language A, if A is regular, then A is also context-free. You may assume that the statements from the previous Closure under Context-Free Languages problem are proved. R is a regular expression if RR is: a for some a∈alphabet Σ, the empty string ε, the empty set ∅, R1∪R2, sometimes written R1∣R2, where R1 and R2 are regular expressions, R1∘R2, sometimes written R1R2, where R1 and...

Define lemma? What is Proof by Contraposition? Define Proof?

5 Regular => Context-Free Give a proof by induction on regular expressions that: For any language...

5 Regular => Context-Free Give a proof by induction on regular expressions that: For any language A, if A is regular, then A is also context-free. You may assume that the statements from the previous Closure under Context-Free Languages problem are proved.

Show that L2 = {anb2nan : n ≥ 0} is not context-free using the pumping lemma.

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