Question

1 ton of TNT can produce 4.6 x 10⁹ J of energy. A chemist wants to know how to obtain this much energy from acetylene (C₂H₂) and Oxygen (O₂). How much acetylene and Oxygen would be required? Provide the name and structure of the TNT

Reaction between Acetylene and Oxygen: ΔH= -2510 KJ

Answer 1

TNT abrivated as Tri Nitro Tolune and the structure is as follows.

1 ton = 907.185 g

1 ton of TNT produces 4.6 * 10^9 J

Acetylene and Oxygen reaction as follows,

2 C2H2 + 5 O2 -------> 4 CO2 + 2 H2O

2 moles of C2H2 reacts with 5 moles of O2

mass of Acetylene = 2 * 26 g/mol = 52 g of C2H2

mass of O2 = 5 * 32 g/mol = 160 g of O2

Total mass of the reacatnas = 160 + 52 = 212 g

from the given data,

Energy released from C2H2 and O2 combination, E = 2510 Kj

i.e., 212 g of mixture can produce 2510 Kj of enegy

4.6 * 10^9 J of energy requires 212/(2510 * 10^3)*4.6*10^9 g of mixture

                                                      = 388525.89 g

212 g of mixture contains 52 g of C2H2

388525.89 g of C2H2 contains 52/212 * 388525.89 g

                                                       = 95298.803 g of C2H2

212 g of mixture contains 160 g of O2

388525.89 g of mixture contains 160/212*388525.89 g

                                                        = 293227.086 g of O2