Protons having a kinetic energy of 5.00 MeV (1 eV = 1.60 x 10-19 J) are...

Protons having a kinetic energy of 5.00 MeV (1 eV = 1.60 x 10-19 J) are moving in the positive x direction and enter a magnetic field B = 0.025 T directed out of the plane of the page and extending from x = 0 to x = 1.00 m as shown in the Figure below. (a) Ignoring relativistic effects, find the angle α between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field. (b) Calculate the y component of the protons’ momenta as they leave the magnetic field.

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genius_generous answered 1 year ago

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