Question
In: Statistics and Probability
Assume that 20.3% of people have sleepwalked. Assume that in a random sample of 1467 adults,...
Assume that 20.3% of people have sleepwalked. Assume that in a random sample of 1467 adults, 314 have sleepwalked.
a. Assuming that the rate of 20.3% is correct, find the probability that 314 or more of the 1467 adults have sleepwalked.
b. Is that result of 314 or more significantly high?
c. What does the result suggest about the rate of 20.3%?
Solutions
Expert Solution
Population proportion, p = 0.203
Sample size, n = 1467
P(X < A) = P(Z < (A - 
)/
)
= np
= 1467x0.203
= 297.801
= 
= 
= 15.406
a. P(314 or more of the 1467 adults have sleepwalked) = P(X
314)
= 1 - P(X < 313.5) (with continuity correction)
= 1 - P(Z < (313.5 - 297.801)/15.406)
= 1 - P(Z < 1.02)
= 1 - 0.8461
= 0.1539
b. The probability of 314 or more is not less than 0.05. Therefore, it is not significantly high.
c. We do not have enough evidence to suspect that the rate of 20.3% is wrong.
orchestra answered 2 years agoRelated Solutions
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