Assume that 38.7% of people have sleepwalked. Assume that in a random sample of 1527 adults,...

Assume that 38.7% of people have sleepwalked. Assume that in a random sample of 1527 adults, 604 have sleepwalked.

a. Assuming that the rate of 38.7% is correct, find the probability that 604or more of the 1527adults have sleepwalked.

b. Is that result of 604 or more significantly high?

c. What does the result suggest about the rate of 38.7%?

Expert Solution

please rate if it is helpfull

orchestra answered 2 years ago

Assume that .333.3% of people have sleepwalked. Assume that in a random sample of 1488 adults,...

Assume that .333.3% of people have sleepwalked. Assume that in a random sample of 1488 adults, 534 have sleepwalked.a. Assuming that the rate of 333.3% is correct, find the probability that 534 or more of the 1488 adults have sleepwalked.b. Is that result of 534 or more significantly high?c. What does the result suggest about the rate of 333.3%? a. Assuming that the rate of 333.3% is correct, the probability that 534 or more of the 1488 adults have sleepwalked...

Assume that 20.3% of people have sleepwalked. Assume that in a random sample of 1467 adults,...

Assume that 20.3% of people have sleepwalked. Assume that in a random sample of 1467 adults, 314 have sleepwalked. a. Assuming that the rate of 20.3% is correct, find the probability that 314 or more of the 1467 adults have sleepwalked. b. Is that result of 314 or more significantly high? c. What does the result suggest about the rate of 20.3%?

Assume that 23.6% of people have sleepwalked. Assume that in a random sample of 1505 adults,...

Assume that 23.6% of people have sleepwalked. Assume that in a random sample of 1505 adults, 400 have sleepwalked. 1. a. Assuming that the rate of 23.6% is correct, the probability that 400 or more of the 1505 adults have sleepwalked is [ ] b. Is that result of 611 or more significantly high? c. What does the result suggest about the rate of 23.6%? 2. In a study of 437 comma 485 cell phone users, it was found that 54...

ssume that 32.632.6% of people have sleepwalked. Assume that in a random sample of 15011501 adults,...

ssume that 32.632.6% of people have sleepwalked. Assume that in a random sample of 15011501 adults, 532532 have sleepwalked.a. Assuming that the rate of 32.632.6% is correct, find the probability that 532532 or more of the 15011501 adults have sleepwalked.b. Is that result of 532532 or more significantly high?c. What does the result suggest about the rate of 32.632.6%? a. Assuming that the rate of 32.632.6% is correct, the probability that 532532 or more of the 15011501 adults have sleepwalked...

In 2012, the General Social Survey asked a random sample of adults, "Compared to most people,...

In 2012, the General Social Survey asked a random sample of adults, "Compared to most people, how informed are you about politics?" Suppose that the following are the data classified by their responses to this question and their age group (the data has been modified slightly for testing purposes): Not at All A little Somewhat Very Extremely Age 20-29 7 29 28 13 0 Age 30-39 16 29 56 22 8 Age 40-49 3 24 50 26 14 Age 50...

Mimi conducted a survey on a random sample of 100 adults. 58 adults in the sample...

Mimi conducted a survey on a random sample of 100 adults. 58 adults in the sample chose banana as his / her favorite fruit. Construct a 95% confidence interval estimate of the proportion of adults whose favorite fruit is banana. Show all work. Just the answer, without supporting work, will receive no credit.

The waiting times (in minutes) of a random sample of 20 people at a bank have...

The waiting times (in minutes) of a random sample of 20 people at a bank have a sample standard deviation of 3.4 minutes. Construct a confidence interval for the population variance sigma squared and the population standard deviation sigma. Use a 90 % level of confidence. Assume the sample is from a normally distributed population.

In a random sample of 1,000 people, it is found that 7.7% have a liver ailment....

In a random sample of 1,000 people, it is found that 7.7% have a liver ailment. Of those who have a liver ailment, 6% are heavy drinkers, 55% are moderate drinkers, and 39% are nondrinkers. Of those who do not have a liver ailment, 9% are heavy drinkers, 45% are moderate drinkers, and 46% are nondrinkers. If a person is chosen at random, and he or she is a heavy drinker, what is the probability of that person having a...

A 2020 Pew Research survey asked a random sample of 4860 American adults if they have...

A 2020 Pew Research survey asked a random sample of 4860 American adults if they have ever used online dating (website or mobile app) and found that 30 percent of respondents had ever done so. Q1 Which math symbol(s) would represent the cited value 30 percent? mm nn x¯x¯ x¯1−x¯2x¯1−x¯2 σσ CC zz μdiffμdiff μμ tt p^p^ x¯diffx¯diff μ1−μ2μ1−μ2 Q2 (Please answer very clear and detail) Obtain a 95% confidence interval estimating the prevalence (rate) of online dating among American...

According to a recent study, 22.6% of adults are smokers. A random sample of 300 adults...

According to a recent study, 22.6% of adults are smokers. A random sample of 300 adults is obtained. Describe the sampling distribution of the sample proportion of adults who smoke. In a random sample of 300 adults, what is the probability that at least 50 are smokers? Would it be unusual if a random sample of 300 adults resulted in 17% or less being smokers?

Question