In: Chemistry
Calculate ΔHrxn for the following reaction:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Use the following reactions and given ΔH′s.
2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH =
-824.2 kJ
CO(g)+1/2O2(g)→CO2(g), ΔH =
-282.7 kJ
Desired reaction is
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Given reactions
Reaction -1 :
2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH =
-824.2 kJ
Reaction 2 :
CO(g)+1/2O2(g)→CO2(g), ΔH =
-282.7 kJ
We use Hess’s law
Lets reverse reaction first
Fe2O3(s) → 2Fe(s)+3/2O2(g) ΔH = 824.2 kJ (sing is changed while reversing)
Multiply reaction by 3
3 CO(g)+3/2O2(g)→3 CO2(g), ΔH = 3x (-282.7 kJ)
Lets add these two reactions
Fe2O3(s) → 2Fe(s)+3/2O2(g) ΔH = 824.2 kJ
3 CO(g)+3/2O2(g)→3 CO2(g), ΔH = 3x (-282.7 kJ)
------------------------------------------------------------------
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) DeltH = 824.2 + ( 3* - 282.7 kJ )
= -23.9 kJ
(Delta H of reactions added when reactions are added)
Answer : Delta Hrxn = -23.9 kJ