Question

In: Other

a) Calculate the mean free path of a gas with an average speed of 10 m/s...

a) Calculate the mean free path of a gas with an average speed of 10 m/s with collision frequency of 10 s-1. b) Calculate the mean free path of a gas with a density of 10 particles/cm3 and molecular diameter of 0.1 nm. c) Calculate the mean free path of a gas in a 1 cm3 container with 10 molecules and molecular diameter of 0.1 nm.

Solutions

Expert Solution


Related Solutions

The average molecular speed in a sample of  gas at a certain temperature is 276 m/s. The...
The average molecular speed in a sample of  gas at a certain temperature is 276 m/s. The average molecular speed in a sample of NO2 gas is ____ m/s at the same temperature.
The mean free path of neon is 6.4 x 10^-2 m at a pressure of 1.00...
The mean free path of neon is 6.4 x 10^-2 m at a pressure of 1.00 x 10^-4 atm and 298 K. A neon atom has a mass of 3.351 x 10^-26 kg. Calculate the collision cross section and the collision frequency of neon under these conditions.
3. Calculate the collision frequency, binary collision number, mean free path, and viscosity for Ar gas...
3. Calculate the collision frequency, binary collision number, mean free path, and viscosity for Ar gas at 298 K and 1.0 atm pressure. The collision diameter of Ar is 3.64 Å. Assume that Ar behaves ideally under these conditions.
Derive an expression of the mean free path of a gas molecule assuming a hard sphere...
Derive an expression of the mean free path of a gas molecule assuming a hard sphere collision. Calculate the ratio of the mean free path of CO molecules in a vessel at a pressure P1=10-4 Torr at 300 K to that at a pressure P2=10-9 Torr at the same temperature. (CO molecules d =0.73nm)
Calculate the average speed, collision frequency, average free travel and the total number of shocks for...
Calculate the average speed, collision frequency, average free travel and the total number of shocks for 1 mole of nitrogen found in a 0.5 L container at a temperature of 280 K. (σ = 0.4 nm2)
Consider a proton moving with a speed of 7.0 × 103 m/s. a) Calculate the de...
Consider a proton moving with a speed of 7.0 × 103 m/s. a) Calculate the de Broglie wavelength of this proton. Consider an electron having a de Broglie wavelength that matches that of the proton found in part a). b) Calculate the speed of this electron. c) Consider an electron and a proton with precisely the same momentum. How do their de Broglie wavelength’s compare?
An electron at point A in the figure has a speed of 1.42×10^6 m/s.
An electron at point A in the figure has a speed of 1.42×10∧6 m/s. (a) Find the direction of the magnetic field that will cause the electron to follow the semicircular path from A to B. (b) Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B. (c) Find the time required for the electron to move from A to B. (d) Find the direction of the magnetic field, that...
A proton is traveling with a speed of (4.010±0.018)× 10 5 m/s . Part A With...
A proton is traveling with a speed of (4.010±0.018)× 10 5 m/s . Part A With what maximum precision can its position be ascertained? Express your answer using two significant figures. ?x? ____ m
A basket ball moving to the right at a speed of 10 m/s makes a head-on...
A basket ball moving to the right at a speed of 10 m/s makes a head-on collision with a ping-pong ball moving to the left at 15 m/s. What will be the speed of the ping-pong ball after the collision. Ignore the air resistance.
A 10 g marble slides to the left at a speed of 0.4 m/s along a...
A 10 g marble slides to the left at a speed of 0.4 m/s along a frictionless surface. It has a head-on, elastic collision with a larger, 30 g marble sliding to the right at 0.2 m/s. Since the collision is head-on, all motion is along the x-axis. a. Find the total kinetic energy AND the total momentum before the collision b. The marbles bounce off each other elastically. Each marble has a different velocity after the collision. The lighter...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT