Question

Suppose 223 subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20 % of users develop nausea.

a) Identify the null and alternative hypothesis

b) Identify the test statistic for this hypothesis test.

c) Identify the P-value for this hypothesis test.

d) Identify the conclusion for this hypothesis test.

Please answer all 4 parts of the question, and only do so if you are 100% certain of the answer, and please be neat. Thank you very much :)

Answer 1

p: Proportion of users who develop nausea

a)

Null hypotheis : Ho : p=0.20

Alternative Hypothesis : Ha: p >0.20

b)

Hypothesized proportion :po =0.20

Number of subjects who are treated with a drug that is used to treat pain: n = 223

Number of subjects of the treated who developed nausea : x = 51

Sample proportion of subjects who of the treated developed nausea: = 51/223 = 0.2287

Significance level : =0.05

Test Statistic for this hypothesis test

Test Statistic for this hypothesis test =1.0715

c)

For right tailed test :

P-value = 0.142

d)

As P-Value i.e. is greater than Level of significance i.e (P-value:0.142 > 0.05:Level of significance); Fail to Reject Null Hypothesis

Conclusion : Fail to Reject the null hypothesis.

At 0.05 significance level , there is not sufficient evidence to conclude that more than 20 % of users develop nausea