Question

Suppose 200 subjects are treated with a drug that is used to treat pain and 55 of them developed nausea. Use a 0.01 significance level to test the claim that more than 20​% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0​: pequals0.20 Upper H 1​: pnot equals0.20 B. Upper H 0​: pequals0.20 Upper H 1​: pgreater than0.20 Your answer is correct.C. Upper H 0​: pgreater than0.20 Upper H 1​: pequals0.20 D. Upper H 0​: pequals0.20 Upper H 1​: pless than0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is nothing. ​(Round to two decimal places as​ needed.) Identify the p-value as well as the conclusion for hypothesis test.

Answer 1

Null hypothesis      

               
                      
Alternative hypothesis      

               
                      
We have for given example,                      
Population proportion value is =0.2                  
x=55                  
                      
n=200                  
Level of significance =   0.01                  
Estimate for sample proportion
                      
Z test statistic formula for proportion


=2.65
P value is =0.0040..............by using Z table or by using Excel command NORMSDIST(2.65)

P value is =0.0040 <0.01

Therefore, we reject H0 at

We have sufficient evidence at to say that more than 20​% of users develop nausea.