In: Statistics and Probability
Suppose 241 241 subjects are treated with a drug that is used to treat pain and 51 51 of them developed nausea. Use a 0.10 0.10 significance level to test the claim that more than 20 20?% of users develop nausea.
Total number of subjet treated with a drug : n= 241
Number of subjects who developed nausea : x = 51
To Test the Claim more than 20% of users develop nausea; i.e proportion of users develop nausea > 0.20
Null hypothesis : Ho :p =po (:0.20)
Alternate hypothesis : Ha :p > po (:0.20) :Right Tailed test
n : Sample Size
Sample Proportion
: Hypothesied Proportion
Given | |
Hypothesied Proportion : | 0.2 |
Number of subjects who developed nausea x | 51 |
Number of Trails : Sample Size : n | 241 |
Sample Proportion : : x/n (i.e 51/241) | 0.2116 |
Level of significance | 0.10 |
For Right Tailed Test: Reject null hypothesis if Calculated value of Z is Greater than Critical Value ;
Critical Value of Z :
As Calculated Value of Z is less than Critical Value i.e. ( 0.4502<1.2816 ); Fail to Reject Null Hypothesis
Not sufficent evidence to reject the claim that percentage of users who develope nausea is 20%