Question

In: Statistics and Probability

For the data below, write an appropriate two-tailed, nondirectional null and alternative hypothesis, calculate the df,...

  1. For the data below, write an appropriate two-tailed, nondirectional null and alternative hypothesis, calculate the df, and find the critical value. (up to 10 points)

                  X                                             Y

Years of Education                 Number of Arrests

                  12                                            5

                  9                                              9

                  17                                            0

                  15                                            0

                  13                                            2

                  10                                            6

  1. What is the coefficient of determination? Describe how to calculate the coefficient of determination. What information does this give us? (up to 5 points)
  1. A professor calculated a correlation coefficient of 0.65 in a recent analysis. Based on this value, calculate the percentage of variance in the dependent variable is attributable to the independent variable? Don’t forget to interpret your results. (up to 5 points)

Solutions

Expert Solution

1)

ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 76 22 45.33333333 65.3 -51.67
mean 12.67 3.67 SSxx SSyy SSxy

sample size ,   n =   6          
here, x̅ = Σx / n=   12.67   ,     ȳ = Σy/n =   3.67  
                  
SSxx =    Σ(x-x̅)² =    45.3333          
SSxy=   Σ(x-x̅)(y-ȳ) =   -51.7          
                  
estimated slope , ß1 = SSxy/SSxx =   -51.7   /   45.333   =   -1.1397
                  
intercept,   ß0 = y̅-ß1* x̄ =   18.1029          
                  
so, regression line is   Ŷ =   18.1029   +   -1.1397   *x
                  
SSE=   (SSxx * SSyy - SS²xy)/SSxx =    6.449          
                  
std error ,Se =    √(SSE/(n-2)) =    1.270          
                  
correlation coefficient ,    r = Sxy/√(Sx.Sy) =   -0.9494          
                  
1)coefficient of determination = R² =    (Sxy)²/(Sx.Sy) =    0.9013

2)It means 90.13 % of variatiion in Y(Number of Arrests) can be explained by X(Years of Education)

3)

R = 0.65

R square = 0.4225


t means 42.25% of variatiion in Y(Number of Arrests) can be explained by X(Years of Education)

-----------------------------------------------------------

Ho:   ρ = 0       tail=   2  
Ha:   ρ ╪ 0              
n=   6              
alpha,α =    0.01              
correlation , r=   -0.9494              
t-test statistic = r*√(n-2)/√(1-r²) =        -6.044          
DF=n-2 =   4              
  
critical t-value =    4.6041             

Please revert in case of any doubt.

Please upvote. Thanks in advance


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