In: Math
Each value represents the number of mistakes (defects) found on a student loan application. Values for 50 consecutive loan applications are given. Calculate the appropriate centerline and 3-sigma control limits for the c-chart, and then plot the data and create a control chart. Does the process appear to be in a state of statistical control? Why or why not?
Upper control limit (UCL) =
Centerline (CL) =
Lower control limit (LCL) =
Process in statistical control?
Expense Report Auditing
Week | Number of Reports Reviewed | Reports Non-conforming | Proportion Non-conforming |
4-Nov | 30 | 8 | 0.267 |
11-Nov | 30 | 6 | 0.200 |
18-Nov | 30 | 9 | 0.300 |
25-Nov | 30 | 7 | 0.233 |
2-Dec | 30 | 4 | 0.133 |
9-Dec | 30 | 10 | 0.333 |
16-Dec | 30 | 7 | 0.233 |
23-Dec | 30 | 7 | 0.233 |
30-Dec | 30 | 7 | 0.233 |
6-Jan | 30 | 7 | 0.233 |
13-Jan | 30 | 8 | 0.267 |
20-Jan | 30 | 11 | 0.367 |
27-Jan | 30 | 9 | 0.300 |
3-Feb | 30 | 8 | 0.267 |
10-Feb | 30 | 4 | 0.133 |
17-Feb | 30 | 6 | 0.200 |
24-Feb | 30 | 8 | 0.267 |
3-Mar | 30 | 8 | 0.267 |
10-Mar | 30 | 8 | 0.267 |
17-Mar | 30 | 4 | 0.133 |
Answer:
The given data is,
Week | Number of Reports Reviewed | Reports Non-conforming | Proportion Non-conforming |
04-Nov | 30 | 8 | 0.267 |
11-Nov | 30 | 6 | 0.2 |
18-Nov | 30 | 9 | 0.3 |
25-Nov | 30 | 7 | 0.233 |
02-Dec | 30 | 4 | 0.133 |
09-Dec | 30 | 10 | 0.333 |
16-Dec | 30 | 7 | 0.233 |
23-Dec | 30 | 7 | 0.233 |
30-Dec | 30 | 7 | 0.233 |
06-Jan | 30 | 7 | 0.233 |
13-Jan | 30 | 8 | 0.267 |
20-Jan | 30 | 11 | 0.367 |
27-Jan | 30 | 9 | 0.3 |
03-Feb | 30 | 8 | 0.267 |
10-Feb | 30 | 4 | 0.133 |
17-Feb | 30 | 6 | 0.2 |
24-Feb | 30 | 8 | 0.267 |
03-Mar | 30 | 8 | 0.267 |
10-Mar | 30 | 8 | 0.267 |
17-Mar | 30 | 4 | 0.133 |
We have to calculate the average number of non-conforming reports.
where N is the total number of items and ci the number of reports non-conforming per item.
Therefore,
Centerline, upper control limit and the lower control limit can be determined as below:
Centerline (CL) = = 7.3
Uppler control limit (UCL) =
Lower control limit (LCL) =
Practically, the lower control limit cannot be negative; hence, the lower control limit is taken as zero.
i.e. Lower control limit (LCL) = 0.
Then after plotting the above control limits and the reports non-conforming, the c-chart is as below:
The above c-chart clearly exhibits that all the points are within the control limits. Hence, it can be said that the process is in statistical control with an average of 7.3 non-conforming reports per lot reviewed.