Solve the given initial-value problem. y'' + 4y' + 4y = (5 +
x)e^(−2x) y(0) = 3, y'(0) = 6
Arrived at answer
y(x)=3e^{-2x}+12xe^{-2x}+(15/2}x^2e^{-2x}+(5/6)x^3e^{-2x) by using
variation of parameters but it was incorrect.
Solve the following differential equations using method of
undetermined coefficients:
a) y''-5y'+6y=2t-3e^(-4t)
b)y''+4y=5cos(2x)
c)y''''-y''=3x+yxe^(-x)
d)y''-3y'-4y=3+e^(4t)