Question

Label these solutions 3% NaCl, DI H20, 5% glucose, 12% glucose, 1% glucose as hypertonic, hypotonic, or isotonic. Also state what would happen to the red blood cell (crenation,stays nice,hemolysis)

Answer 1

Osmotic pressure = i * C * R * T

i = vant hoff factor

C = concentration of solution

R = solution constant

T = temperature of the solution

3% NaCl solution means 3 g of NaCl in 100 mL of solution.

molarity of NaCl soution = 3/58.5 * 1000/100

                         = 0.05128 M

but NaCl -----> Na+ + Cl-

Osmotic pressure = 2 * 0.05128 * 0.083 * 298

                 = 2.5367 atm

5% of glucose solution means 5 g of glucose in 100 mL of solution.

molarity of Glucose solution = 5/180 * 1000/100

                             = 0.2778 M
Glucose ------> Glucose

Osmotic Pressure = 1 * 0.2778 * 0.083 * 298

                 = 6.8711 atm

12% of glucose solution means 12 g of glucose in 100 mL of solution.

molarity of Glucose solution = 12/180 * 1000/100

                             = 0.6667 M
Glucose ------> Glucose

Osmotic Pressure = 1 * 0.6667 * 0.083 * 298

                 = 16.49 atm

1% of glucose solution means 1 g of glucose in 100 mL of solution.

molarity of Glucose solution = 1/180 * 1000/100

                             = 0.0555 M
Glucose ------> Glucose

Osmotic Pressure = 1 * 0.0555 * 0.083 * 298

                 = 1.3727

SO 12% glicose solution is Hypertonic solution compare to other solutions due to greater osmotic pressure and has high number of particles

and 1% glucose solution is Hypotonic solution compare to other solutions due to lower osmotic pressure and has less number of particles