Question

In: Chemistry

A lab assistant needs to prepare solutions of ZnSO4, NaCl, Na2CO3, Fe2(SO4)3 and FeCl3 with identical...

A lab assistant needs to prepare solutions of ZnSO4, NaCl, Na2CO3, Fe2(SO4)3 and FeCl3 with identical ionic strengths of I = 1.2 M. What concentration of these salts should he/she use?

Solutions

Expert Solution

Ionic strength of a solution is given by

I = (b+z+2 + b-z-2)/2

Here b+, b- are the concentrations of cation and anions, respectively.

b+ = n+b, b- = n-b, 'b' is the concentration of solution

n+, n- are the no. of cations and anions, respectively.

ZnSO4

I = (1b*22 + 1b*22)/2

1.2 = 4b, i.e. b = 0.3 M

Therefore, the concentration of ZnSO4 solution = 0.3 M

NaCl

I = (1b*12 + 1b*12)/2

1.2 = b

Therefore, the concentration of NaCl solution = 1.2 M

Na2CO3

I = (2b*12 + 1b*22)/2

1.2 = 3b, i.e. b = 0.4 M

Therefore, the strength of Na2CO3 solution = 0.4 M

Fe2(SO4)3

I = (2b*32 + 3b*22)/2​

1.2 = 15b, i.e. b = 0.08 M

Therefore, the strength of Fe2(SO4)3 solution = 0.08 M

FeCl3

I = (1b*32 + 3b*12)/2​​

1.2 = 6b, i.e. b = 0.2 M

Therefore, the strength of FeCl3 solution = 0.2 M


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