Question

In: Math

How much does a sleeping bag cost? Let's say you want a sleeping bag that should...

How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.

35 110 65 90 90 35 30 23 100 110
105 95 105 60 110 120 95 90 60 70

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.)

x = $
s = $


(b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.)

lower limit     $
upper limit     $

Solutions

Expert Solution

Let X denote the prices ($) for sleeping bags

The sample size is n = 20. The provided sample data along with the data required to compute the sample mean and sample variance are shown in the table below:

X X2
5 25
110 12100
65 4225
90 8100
90 8100
35 1225
30 900
23 529
100 10000
110 12100
105 11025
95 9025
105 11025
60 3600
110 12100
120 14400
95 9025
90 8100
60 3600
70 4900
Sum = 1568 144104

The sample mean is computed as follows:

mean = $ 78.4

Also, the sample variance is

Therefore, the sample standard deviation s is

s = $ 33.382

We need to construct the90% confidence interval for the population mean . The following information is provided:

Sample Mean 78.4
Population Standard Deviation 333.382
Sample Size (N) 20

The critical value for is . The corresponding confidence interval is computed as shown below:

CI = ( −44.22 , 201.02 )​

Therefore, based on the data provided, the 90% confidence interval for the population mean is -44.22 < < 201.02, which indicates that we are 90% confident that the true population mean is contained by the interval (-44.2, 201.02).

lower limit = $ -44.22

upper limit = $ 201.02

In case of cost the correct answer may be 0 also, for the lower limit. Since the cost can not be negative


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