In: Math
How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.
| 35 | 110 | 65 | 90 | 90 | 35 | 30 | 23 | 100 | 110 |
| 105 | 95 | 105 | 60 | 110 | 120 | 95 | 90 | 60 | 70 |
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.)
| x = | $ |
| s = | $ |
(b) Using the given data as representative of the population of
prices of all summer sleeping bags, find a 90% confidence interval
for the mean price μ of all summer sleeping bags. (Round
your answers to two decimal places.)
| lower limit | $ |
| upper limit | $ |
Let X denote the prices ($) for sleeping bags
The sample size is n = 20. The provided sample data along with
the data required to compute the sample mean
and sample
variance
are shown in the
table below:
| X | X2 | |
| 5 | 25 | |
| 110 | 12100 | |
| 65 | 4225 | |
| 90 | 8100 | |
| 90 | 8100 | |
| 35 | 1225 | |
| 30 | 900 | |
| 23 | 529 | |
| 100 | 10000 | |
| 110 | 12100 | |
| 105 | 11025 | |
| 95 | 9025 | |
| 105 | 11025 | |
| 60 | 3600 | |
| 110 | 12100 | |
| 120 | 14400 | |
| 95 | 9025 | |
| 90 | 8100 | |
| 60 | 3600 | |
| 70 | 4900 | |
| Sum = | 1568 | 144104 |
The sample mean
is computed as
follows:



mean = $ 78.4
Also, the sample variance
is



Therefore, the sample standard deviation s is



s = $ 33.382
We need to construct the90% confidence interval for the
population mean
. The following
information is provided:
Sample Mean ![]() |
78.4 |
Population Standard Deviation ![]() |
333.382 |
| Sample Size (N) | 20 |
The critical value for
is
. The corresponding confidence interval is computed as shown
below:


CI = ( −44.22 , 201.02 )
Therefore, based on the data provided, the 90% confidence
interval for the population mean is -44.22 <
< 201.02, which
indicates that we are 90% confident that the true population mean
is contained by the interval (-44.2, 201.02).
lower limit = $ -44.22
upper limit = $ 201.02
In case of cost the correct answer may be 0 also, for the lower limit. Since the cost can not be negative