In: Statistics and Probability
How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.
35 | 110 | 40 | 100 | 65 | 70 | 30 | 23 | 100 | 110 |
105 | 95 | 105 | 60 | 110 | 120 | 95 | 90 | 60 | 70 |
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.)
x = | $ |
s = | $ |
(b) Using the given data as representative of the population of
prices of all summer sleeping bags, find a 90% confidence interval
for the mean price μ of all summer sleeping bags. (Round
your answers to two decimal places.)
lower limit | $ |
upper limit | $ |
Solution:- Given that samples :
35,110,40,100,65,70,30,23,100,110,105,95,105,60,110,120,95,90,60,70
(a) X = 79.65
mean = sum of terms/number of terms
= 1593/20
= 79.65
standard deviation : s = 30.35
(b) 90% confidence interval for the mean price μ of all summer sleeping bags :
lower limit 67.92 $
upper limit 91.39 $